5) $$(3\frac{1}{15}-1\frac{1}{15}:1\frac{3}{5}+\frac{2}{5})\cdot2\frac{1}{7}-1\frac{1}{7}$$

Решим пример по действиям:

1) $$3\frac{1}{15}-1\frac{1}{15} = \frac{46}{15} - \frac{16}{15} = \frac{30}{15} = 2$$

2) $$1\frac{3}{5} = \frac{8}{5}$$

3) $$2:\frac{8}{5} = 2 \cdot \frac{5}{8} = \frac{10}{8} = \frac{5}{4}$$

4) $$\frac{5}{4} + \frac{2}{5} = \frac{5\cdot5 + 2\cdot4}{20} = \frac{25+8}{20} = \frac{33}{20}$$

5) $$2\frac{1}{7} = \frac{15}{7}$$

6) $$1\frac{1}{7} = \frac{8}{7}$$

7) $$\frac{33}{20} \cdot \frac{15}{7} = \frac{33\cdot15}{20\cdot7} = \frac{33\cdot3}{4\cdot7} = \frac{99}{28}$$

8) $$\frac{99}{28} - \frac{8}{7} = \frac{99}{28} - \frac{8\cdot4}{7\cdot4} = \frac{99}{28} - \frac{32}{28} = \frac{67}{28} = 2\frac{11}{28}$$

Ответ: $$2\frac{11}{28}$$