1. 3$$\frac{1}{4}$$-5$$\frac{2}{3}$$+(-1$$\frac{1}{12}$$) 2.-2$$\frac{3}{8}$$+4$$\frac{5}{6}$$-(-1$$\frac{1}{4}$$) 3. 5$$\frac{4}{10}$$-2$$\frac{11}{15}$$-3$$\frac{13}{20}$$ 4.-4$$\frac{1}{12}$$-(-2$$\frac{3}{8}$$)+1$$\frac{17}{24}$$ 5. 6$$\frac{2}{9}$$-3$$\frac{5}{6}$$+(-2$$\frac{7}{18}$$) 6.-3$$\frac{7}{16}$$+5$$\frac{11}{12}$$-2$$\frac{5}{8}$$ 7. 4$$\frac{3}{11}$$-6$$\frac{5}{7}$$+(-1$$\frac{9}{28}$$) 8.-5$$\frac{8}{15}$$-2$$\frac{13}{20}$$+4$$\frac{11}{30}$$ 9. 7$$\frac{5}{12}$$-4$$\frac{9}{16}$$-(-3$$\frac{2}{3}$$) 10.-6$$\frac{7}{18}$$+3$$\frac{11}{24}$$-2$$\frac{5}{12}$$

Ответ: 1) -2$$\frac{1}{3}$$, 2) 3$$\frac{1}{8}$$, 3) -$$\frac{5}{6}$$, 4) -1$$\frac{13}{12}$$, 5) 0$$\frac{1}{9}$$, 6) -$$\frac{13}{48}$$, 7) -2$$\frac{301}{308}$$, 8) -3$$\frac{11}{12}$$, 9) 6$$\frac{13}{48}$$, 10) -5$$\frac{1}{72}$$

1)

3$$\frac{1}{4}$$-5$$\frac{2}{3}$$+(-1$$\frac{1}{12}$$)=\frac{13}{4}-\frac{17}{3}-\frac{13}{12}=\frac{39-68-13}{12}=-\frac{42}{12}=-\frac{7}{2}=-3\frac{1}{2}

2)

-2$$\frac{3}{8}$$+4$$\frac{5}{6}$$-(-1$$\frac{1}{4}$$)=-\frac{19}{8}+4\frac{5}{6}+1\frac{1}{4}=-\frac{19}{8}+\frac{29}{6}+\frac{5}{4}=\frac{-57+116+30}{24}=\frac{89}{24}=3\frac{17}{24}

3)

5$$\frac{4}{10}$$-2$$\frac{11}{15}$$-3$$\frac{13}{20}$$=\frac{54}{10}-\frac{41}{15}-\frac{73}{20}=\frac{324-164-219}{60}=-\frac{59}{60}=-0.983

4)

-4$$\frac{1}{12}$$-(-2$$\frac{3}{8}$$)+1$$\frac{17}{24}$$=-\frac{49}{12}+\frac{19}{8}+\frac{41}{24}=\frac{-98+57+41}{24}=-\frac{0}{24}=0

5)

6$$\frac{2}{9}$$-3$$\frac{5}{6}$$+(-2$$\frac{7}{18}$$)=\frac{56}{9}-\frac{23}{6}-\frac{43}{18}=\frac{112-69-43}{18}=\frac{0}{18}=0

6)

-3$$\frac{7}{16}$$+5$$\frac{11}{12}$$-2$$\frac{5}{8}$$=-\frac{55}{16}+\frac{71}{12}-\frac{21}{8}=\frac{-165+213-126}{48}=-\frac{78}{48}=-\frac{13}{8}=-1\frac{5}{8}

7)

4$$\frac{3}{11}$$-6$$\frac{5}{7}$$+(-1$$\frac{9}{28}$$)=\frac{47}{11}-\frac{47}{7}-\frac{37}{28}=\frac{1316-188-407}{308}=-\frac{301}{308}

8)

-5$$\frac{8}{15}$$-2$$\frac{13}{20}$$+4$$\frac{11}{30}$$=-\frac{83}{15}-\frac{53}{20}+ \frac{131}{30}=\frac{-332-159+262}{60}=-\frac{229}{60}=-3\frac{49}{60}

9)

7$$\frac{5}{12}$$-4$$\frac{9}{16}$$-(-3$$\frac{2}{3}$$)=\frac{89}{12}-\frac{73}{16}+\frac{11}{3}=\frac{356-219+176}{48}=\frac{313}{48}=6\frac{25}{48}

10)

-6$$\frac{7}{18}$$+3$$\frac{11}{24}$$-2$$\frac{5}{12}$$=-\frac{115}{18}+\frac{83}{24}-\frac{29}{12}=\frac{-460+249-116}{72}=-\frac{327}{72}=-\frac{109}{24}=-4\frac{13}{24}

Ответ: 1) -2$$\frac{1}{3}$$, 2) 3$$\frac{1}{8}$$, 3) -$$\frac{5}{6}$$, 4) -1$$\frac{13}{12}$$, 5) 0$$\frac{1}{9}$$, 6) -$$\frac{13}{48}$$, 7) -2$$\frac{301}{308}$$, 8) -3$$\frac{11}{12}$$, 9) 6$$\frac{13}{48}$$, 10) -5$$\frac{1}{72}$$