2) $$(6\frac{3}{4}-5\frac{1}{8}:1\frac{9}{32}) \cdot \frac{5}{11}$$

2) $$(6\frac{3}{4}-5\frac{1}{8}:1\frac{9}{32}) \cdot \frac{5}{11} = (\frac{27}{4} - \frac{41}{8} : \frac{41}{32}) \cdot \frac{5}{11} = (\frac{27}{4} - \frac{41}{8} \cdot \frac{32}{41}) \cdot \frac{5}{11} = (\frac{27}{4} - 4) \cdot \frac{5}{11} = (\frac{27}{4} - \frac{16}{4}) \cdot \frac{5}{11} = \frac{11}{4} \cdot \frac{5}{11} = \frac{5}{4} = 1\frac{1}{4}$$ Ответ: $$1\frac{1}{4}$$