1) $$5\frac{6}{7}-3\frac{2}{7}=$$ 2) $$9-\frac{4}{5}=$$ 3) $$6-3\frac{1}{7}=$$ 4) $$2\frac{1}{2}+3\frac{1}{2}=$$ 5) $$3\frac{7}{9}+1\frac{1}{9}=$$ 6) $$3+\frac{5}{11}=$$ 7) $$2\frac{1}{7}-\frac{4}{7}=$$ 8) $$1\frac{2}{3}-\frac{4}{7}=$$ 9) $$7\frac{4}{5}-7=$$ 10) $$\frac{3}{8}+4=$$

Решим данные примеры:

1. $$5\frac{6}{7}-3\frac{2}{7}=(5-3)+(\frac{6}{7}-\frac{2}{7})=2+\frac{4}{7}=2\frac{4}{7}$$
2. $$9-\frac{4}{5}=8\frac{5}{5}-\frac{4}{5}=8\frac{1}{5}$$
3. $$6-3\frac{1}{7}=5\frac{7}{7}-3\frac{1}{7}=(5-3)+(\frac{7}{7}-\frac{1}{7})=2+\frac{6}{7}=2\frac{6}{7}$$
4. $$2\frac{1}{2}+3\frac{1}{2}=(2+3)+(\frac{1}{2}+\frac{1}{2})=5+\frac{2}{2}=5+1=6$$
5. $$3\frac{7}{9}+1\frac{1}{9}=(3+1)+(\frac{7}{9}+\frac{1}{9})=4+\frac{8}{9}=4\frac{8}{9}$$
6. $$3+\frac{5}{11}=3\frac{5}{11}$$
7. $$2\frac{1}{7}-\frac{4}{7}=1\frac{8}{7}-\frac{4}{7}=1\frac{4}{7}$$
8. $$1\frac{2}{3}-\frac{4}{7}=\frac{5}{3}-\frac{4}{7}=\frac{5*7}{3*7}-\frac{4*3}{7*3}=\frac{35}{21}-\frac{12}{21}=\frac{23}{21}=1\frac{2}{21}$$
9. $$7\frac{4}{5}-7=\frac{4}{5}$$
10. $$\frac{3}{8}+4=4\frac{3}{8}$$

Ответ: 1) $$2\frac{4}{7}$$; 2) $$8\frac{1}{5}$$; 3) $$2\frac{6}{7}$$; 4) $$6$$; 5) $$4\frac{8}{9}$$; 6) $$3\frac{5}{11}$$; 7) $$1\frac{4}{7}$$; 8) $$1\frac{2}{21}$$; 9) $$\frac{4}{5}$$; 10) $$4\frac{3}{8}$$