Решение примеров

1. $$2\frac{1}{3} \cdot 9 - 1\frac{1}{3} \cdot 3\frac{1}{4} - 2\frac{2}{7} \cdot 3\frac{5}{24} = $$ $$\frac{7}{3} \cdot 9 - \frac{4}{3} \cdot \frac{13}{4} - \frac{16}{7} \cdot \frac{77}{24} = $$ $$21 - \frac{13}{3} - \frac{22}{3} = 21 - \frac{35}{3} = 21 - 11\frac{2}{3} = 9\frac{1}{3}$$

   Ответ: $$9\frac{1}{3}$$

2. $$1\frac{7}{48} \cdot 2\frac{2}{5} - (9\frac{1}{6} \cdot \frac{4}{15} + 2\frac{5}{9}) \cdot \frac{2}{5} = $$ $$\frac{55}{48} \cdot \frac{12}{5} - (\frac{55}{6} \cdot \frac{4}{15} + \frac{23}{9}) \cdot \frac{2}{5} = $$ $$\frac{11}{4} \cdot \frac{1}{1} - (\frac{11}{3} \cdot \frac{2}{3} + \frac{23}{9}) \cdot \frac{2}{5} = $$ $$\frac{11}{4} - (\frac{22}{9} + \frac{23}{9}) \cdot \frac{2}{5} = $$ $$\frac{11}{4} - \frac{45}{9} \cdot \frac{2}{5} = $$ $$\frac{11}{4} - 5 \cdot \frac{2}{5} = $$ $$\frac{11}{4} - 2 = \frac{11}{4} - \frac{8}{4} = \frac{3}{4}$$

   Ответ: $$\frac{3}{4}$$