6-2\frac{7}{8} = 5\frac{8}{8}-2\frac{7}{8} = 3\frac{1}{8}
5\frac{1}{6}+2\frac{3}{15} = 5\frac{5}{30}+2\frac{6}{30} = 7\frac{11}{30}
9\frac{5}{6}-3 = 6\frac{5}{6}
7\frac{1}{4}-3\frac{3}{5} = 7\frac{5}{20}-3\frac{12}{20} = 6\frac{25}{20}-3\frac{12}{20} = 3\frac{13}{20}
2\frac{8}{14}+6\frac{18}{21} = 2\frac{4}{7}+6\frac{6}{7} = 8\frac{10}{7} = 9\frac{3}{7}
10-4\frac{2}{5} = 9\frac{5}{5}-4\frac{2}{5} = 5\frac{3}{5}
8\frac{1}{9}-5\frac{5}{6} = 8\frac{2}{18}-5\frac{15}{18} = 7\frac{20}{18}-5\frac{15}{18} = 2\frac{5}{18}
1\frac{3}{10}+3\frac{2}{5} = 1\frac{3}{10}+3\frac{4}{10} = 4\frac{7}{10}
9\frac{1}{3}-5\frac{2}{7} = 9\frac{7}{21}-5\frac{6}{21} = 4\frac{1}{21}
4\frac{2}{3}-1\frac{1}{6} = 4\frac{4}{6}-1\frac{1}{6} = 3\frac{3}{6} = 3\frac{1}{2}
6\frac{2}{7}+10 = 16\frac{2}{7}
7\frac{11}{16}+2\frac{13}{24} = 7\frac{33}{48}+2\frac{26}{48} = 9\frac{59}{48} = 10\frac{11}{48}
12-5\frac{13}{18} = 11\frac{18}{18}-5\frac{13}{18} = 6\frac{5}{18}
10\frac{18}{25}-8 = 2\frac{18}{25}
8\frac{11}{20}+5\frac{13}{24} = 8\frac{66}{120}+5\frac{65}{120} = 13\frac{131}{120} = 14\frac{11}{120}
9\frac{17}{24}-7 = 2\frac{17}{24}
9-7\frac{18}{20} = 8\frac{20}{20}-7\frac{18}{20} = 1\frac{2}{20} = 1\frac{1}{10}
12\frac{3}{7}+4\frac{11}{9} = 12\frac{27}{63}+4\frac{77}{63} = 16\frac{104}{63} = 17\frac{41}{63}
6\frac{11}{20}+4\frac{7}{15} = 6\frac{33}{60}+4\frac{28}{60} = 10\frac{61}{60} = 11\frac{1}{60}
5\frac{13}{16}+3 = 8\frac{13}{16}
10\frac{1}{18}-4\frac{2}{3} = 10\frac{1}{18}-4\frac{12}{18} = 9\frac{19}{18}-4\frac{12}{18} = 5\frac{7}{18}
8-1\frac{5}{6} = 7\frac{6}{6}-1\frac{5}{6} = 6\frac{1}{6}
7\frac{12}{16}-4 = 3\frac{12}{16} = 3\frac{3}{4}
2\frac{5}{6}+1\frac{3}{4} = 2\frac{10}{12}+1\frac{9}{12} = 3\frac{19}{12} = 4\frac{7}{12}
Ответ: смотри решение выше