Преобразуем смешанные числа в неправильные дроби.
- $$15 \frac{5}{5} = \frac{15 \cdot 5 + 5}{5} = \frac{75 + 5}{5} = \frac{80}{5}$$
- $$13 \frac{1}{2} = \frac{13 \cdot 2 + 1}{2} = \frac{26 + 1}{2} = \frac{27}{2}$$
- $$5 \frac{2}{3} = \frac{5 \cdot 3 + 2}{3} = \frac{15 + 2}{3} = \frac{17}{3}$$
- $$7 \frac{4}{6} = \frac{7 \cdot 6 + 4}{6} = \frac{42 + 4}{6} = \frac{46}{6} = \frac{23}{3}$$
- $$15 \frac{4}{9} = \frac{15 \cdot 9 + 4}{9} = \frac{135 + 4}{9} = \frac{139}{9}$$
- $$19 \frac{3}{5} = \frac{19 \cdot 5 + 3}{5} = \frac{95 + 3}{5} = \frac{98}{5}$$
- $$21 \frac{4}{7} = \frac{21 \cdot 7 + 4}{7} = \frac{147 + 4}{7} = \frac{151}{7}$$
- $$45 \frac{3}{5} = \frac{45 \cdot 5 + 3}{5} = \frac{225 + 3}{5} = \frac{228}{5}$$
- $$11 \frac{1}{5} = \frac{11 \cdot 5 + 1}{5} = \frac{55 + 1}{5} = \frac{56}{5}$$
- $$16 \frac{2}{3} = \frac{16 \cdot 3 + 2}{3} = \frac{48 + 2}{3} = \frac{50}{3}$$
- $$23 \frac{5}{2} = \frac{23 \cdot 2 + 5}{2} = \frac{46 + 5}{2} = \frac{51}{2}$$
- $$37 \frac{1}{2} = \frac{37 \cdot 2 + 1}{2} = \frac{74 + 1}{2} = \frac{75}{2}$$
- $$25 \frac{3}{4} = \frac{25 \cdot 4 + 3}{4} = \frac{100 + 3}{4} = \frac{103}{4}$$
- $$38 \frac{3}{4} = \frac{38 \cdot 4 + 3}{4} = \frac{152 + 3}{4} = \frac{155}{4}$$
- $$15 \frac{5}{7} = \frac{15 \cdot 7 + 5}{7} = \frac{105 + 5}{7} = \frac{110}{7}$$
- $$10 \frac{9}{11} = \frac{10 \cdot 11 + 9}{11} = \frac{110 + 9}{11} = \frac{119}{11}$$
- $$12 \frac{4}{10} = \frac{12 \cdot 10 + 4}{10} = \frac{120 + 4}{10} = \frac{124}{10} = \frac{62}{5}$$
Ответ:
- $$\frac{80}{5}$$
- $$\frac{27}{2}$$
- $$\frac{17}{3}$$
- $$\frac{23}{3}$$
- $$\frac{139}{9}$$
- $$\frac{98}{5}$$
- $$\frac{151}{7}$$
- $$\frac{228}{5}$$
- $$\frac{56}{5}$$
- $$\frac{50}{3}$$
- $$\frac{51}{2}$$
- $$\frac{75}{2}$$
- $$\frac{103}{4}$$
- $$\frac{155}{4}$$
- $$\frac{110}{7}$$
- $$\frac{119}{11}$$
- $$\frac{62}{5}$$