14) 7\frac{5}{6}-1 = 6\frac{5}{6} 15) 1\frac{3}{16} = \frac{16}{16} - \frac{3}{16} = \frac{13}{16} 16) 14\frac{1}{21} - 4\frac{19}{21} = ? 17) 11\frac{13}{40} - 10\frac{23}{40} = ? 18) 12\frac{7}{11} - 11\frac{10}{11} = ? 19) 17\frac{15}{26} = ? 20) 9\frac{1}{33} - \frac{4}{33} = ? 21) 27\frac{7}{9} - 11\frac{7}{9} = ? 22) 2\frac{7}{42} - 1\frac{13}{42} = ? 23) 8 - 3\frac{1}{12} = ? 24) 1\frac{2}{25} - \frac{11}{25} = ?

Решение:

14) \(7\frac{5}{6}-1 = 6\frac{5}{6}\) 15) \(1\frac{3}{16} = \frac{16}{16} - \frac{3}{16} = \frac{13}{16}\) 16) \(14\frac{1}{21} - 4\frac{19}{21} = 13\frac{22}{21} - 4\frac{19}{21} = (13-4) + (\frac{22}{21} - \frac{19}{21}) = 9 + \frac{3}{21} = 9\frac{3}{21} = 9\frac{1}{7}\) 17) \(11\frac{13}{40} - 10\frac{23}{40} = 11\frac{13}{40} - 10\frac{23}{40} = 10\frac{53}{40} - 10\frac{23}{40} = (10-10) + (\frac{53}{40} - \frac{23}{40}) = 0 + \frac{30}{40} = \frac{3}{4}\) 18) \(12\frac{7}{11} - 11\frac{10}{11} = 11\frac{18}{11} - 11\frac{10}{11} = (11-11) + (\frac{18}{11} - \frac{10}{11}) = 0 + \frac{8}{11} = \frac{8}{11}\) 19) \(17\frac{15}{26} \) (Тут что-то не так, нужно условие) 20) \(9\frac{1}{33} - \frac{4}{33} = 8\frac{34}{33} - \frac{4}{33} = 8 + (\frac{34}{33} - \frac{4}{33}) = 8 + \frac{30}{33} = 8\frac{30}{33} = 8\frac{10}{11}\) 21) \(27\frac{7}{9} - 11\frac{7}{9} = (27-11) + (\frac{7}{9} - \frac{7}{9}) = 16 + 0 = 16\) 22) \(2\frac{7}{42} - 1\frac{13}{42} = 1\frac{49}{42} - 1\frac{13}{42} = (1-1) + (\frac{49}{42} - \frac{13}{42}) = 0 + \frac{36}{42} = \frac{6}{7}\) 23) \(8 - 3\frac{1}{12} = 7\frac{12}{12} - 3\frac{1}{12} = (7-3) + (\frac{12}{12} - \frac{1}{12}) = 4 + \frac{11}{12} = 4\frac{11}{12}\) 24) \(1\frac{2}{25} - \frac{11}{25} = \frac{27}{25} - \frac{11}{25} = \frac{16}{25}\)

Ответ: смотри выше построчно

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