180 \frac{1}{9} - 201 \frac{1}{9} = -187 \frac{2}{9} \frac{4}{5} + \frac{25}{4} = \frac{141}{20} \frac{3}{2} - \frac{9}{5} = - \frac{3}{10} (\frac{11}{8} + \frac{11}{12}) = \frac{19}{24} (\frac{14}{11} + \frac{11}{10}) \frac{11}{10} = \frac{261}{110} (\frac{3}{4} + 2\frac{1}{5}) + 16 =

Решим примеры по действиям.

1. $$180 \frac{1}{9} - 201 \frac{1}{9} = - (201 \frac{1}{9} - 180 \frac{1}{9} ) = - (201 - 180 + \frac{1}{9} - \frac{1}{9}) = -21$$

2. $$\frac{4}{5} + \frac{25}{4} = \frac{4 \cdot 4}{5 \cdot 4} + \frac{25 \cdot 5}{4 \cdot 5} = \frac{16}{20} + \frac{125}{20} = \frac{16 + 125}{20} = \frac{141}{20} = 7 \frac{1}{20}$$

3. $$\frac{3}{2} - \frac{9}{5} = \frac{3 \cdot 5}{2 \cdot 5} - \frac{9 \cdot 2}{5 \cdot 2} = \frac{15}{10} - \frac{18}{10} = \frac{15 - 18}{10} = - \frac{3}{10}$$

4. $$(\frac{11}{8} + \frac{11}{12}) = \frac{11 \cdot 3}{8 \cdot 3} + \frac{11 \cdot 2}{12 \cdot 2} = \frac{33}{24} + \frac{22}{24} = \frac{33 + 22}{24} = \frac{55}{24} = 2 \frac{7}{24}$$

5. $$(\frac{14}{11} + \frac{11}{10}) \cdot \frac{11}{10} = (\frac{14 \cdot 10}{11 \cdot 10} + \frac{11 \cdot 11}{10 \cdot 11}) \cdot \frac{11}{10} = (\frac{140}{110} + \frac{121}{110}) \cdot \frac{11}{10} = \frac{140 + 121}{110} \cdot \frac{11}{10} = \frac{261}{110} \cdot \frac{11}{10} = \frac{261 \cdot 11}{110 \cdot 10} = \frac{261 \cdot 1}{10 \cdot 10} = \frac{261}{100} = 2 \frac{61}{100} = 2.61$$

6. $$(\frac{3}{4} + 2\frac{1}{5}) + 16 = (\frac{3}{4} + \frac{2 \cdot 5 + 1}{5}) + 16 = (\frac{3}{4} + \frac{11}{5}) + 16 = (\frac{3 \cdot 5}{4 \cdot 5} + \frac{11 \cdot 4}{5 \cdot 4}) + 16 = (\frac{15}{20} + \frac{44}{20}) + 16 = \frac{15 + 44}{20} + 16 = \frac{59}{20} + 16 = 2 \frac{19}{20} + 16 = 18 \frac{19}{20}$$

Ответ: $$180 \frac{1}{9} - 201 \frac{1}{9} = -21$$ $$\frac{4}{5} + \frac{25}{4} = 7 \frac{1}{20}$$ $$\frac{3}{2} - \frac{9}{5} = - \frac{3}{10}$$ $$(\frac{11}{8} + \frac{11}{12}) = 2 \frac{7}{24}$$ $$(\frac{14}{11} + \frac{11}{10}) \frac{11}{10} = 2.61$$ $$(\frac{3}{4} + 2\frac{1}{5}) + 16 = 18 \frac{19}{20}$$