4) 3\frac{1}{6} y + 2\frac{7}{16} y - 4\frac{11}{12} y.

4) 3$$\frac{1}{6}$$ y + 2$$\frac{7}{16}$$ y - 4$$\frac{11}{12}$$ y = y(3$$\frac{1}{6}$$ + 2$$\frac{7}{16}$$ - 4$$\frac{11}{12}$$) = y(3 + 2 - 4 + $$\frac{1}{6}$$ + $$\frac{7}{16}$$ - $$\frac{11}{12}$$) = y(1 + $$\frac{1 \cdot 8}{6 \cdot 8}$$ + $$\frac{7 \cdot 3}{16 \cdot 3}$$ - $$\frac{11 \cdot 4}{12 \cdot 4}$$) = y(1 + $$\frac{8}{48}$$ + $$\frac{21}{48}$$ - $$\frac{44}{48}$$) = y(1 + $$\frac{8 + 21 - 44}{48}$$) = y(1 + $$\frac{-15}{48}$$) = y(1 - $$\frac{5}{16}$$) = y$$\cdot$$\frac{16 - 5}{16}$$ = y$$\cdot$$\frac{11}{16}$$ = $$\frac{11}{16}$$y

Ответ: $$\frac{11}{16}$$y