3) $$\left(\frac{0.216}{0.15}+\frac{2}{3}:\frac{4}{15}\right)+\left(\frac{196}{225}-\frac{7.7}{24\frac{3}{4}}\right)+0.695 : 1.39$$;

$$\left(\frac{0.216}{0.15}+\frac{2}{3}:\frac{4}{15}\right)+\left(\frac{196}{225}-\frac{7.7}{24\frac{3}{4}}\right)+0.695 : 1.39 = \left(\frac{0.216}{0.15}+\frac{2}{3} \cdot \frac{15}{4}\right)+\left(\frac{196}{225}-\frac{7.7}{99/4}\right)+0.695 : 1.39 = \left(1.44+\frac{30}{12}\right)+\left(\frac{196}{225}-\frac{7.7 \cdot 4}{99}\right)+0.5 = 3.94+\left(\frac{196}{225}-\frac{30.8}{99}\right) = 3.94+\left(0.8711-0.3111\right)+0.5=3.94+0.56+0.5=5$$