43) (2²)⁹ ∙ 8 / 2²⁰ =

43) $$\frac{(2^2)^9 \cdot 8}{2^{20}} = \frac{2^{18} \cdot 2^3}{2^{20}} = \frac{2^{18+3}}{2^{20}} = \frac{2^{21}}{2^{20}} = 2^{21-20} = 2^1 = 2$$

Ответ: 2