16) 169 4-3 √1,6-0,9 -> V10 10 10 10-1.2

Решение

16) \[\sqrt{1.6 \cdot 0.9} - \frac{\sqrt{16}}{\sqrt{9}} : \frac{\sqrt{4^2 \cdot 3^2}}{\sqrt{10^2}} - \frac{4 \cdot 3}{10} - 1.2 = \]

\[= \sqrt{1.44} - \frac{4}{3} : \frac{4 \cdot 3}{10} - \frac{12}{10} - 1.2 = \]

\[= 1.2 - \frac{4}{3} : \frac{12}{10} - 1.2 - 1.2 = \]

\[= 1.2 - \frac{4}{3} \cdot \frac{10}{12} - 2.4 = \]

\[= 1.2 - \frac{40}{36} - 2.4 = \]

\[= -1.2 - \frac{10}{9} = \]

\[= -1\frac{2}{10} - 1\frac{1}{9} = \]

\[= -2\frac{18+10}{90} = \]

\[= -2\frac{28}{90} = -2\frac{14}{45}\]