2 3 (√8) 16 1-18 T 113 27 64 252 4 0 (√3) (√5)° 7-2 4-1 200000 3 50 23 h g 2

\[(\sqrt{8})^{\frac{2}{3}} = (8^{\frac{1}{2}})^{\frac{2}{3}} = 8^{\frac{1}{2} \cdot \frac{2}{3}} = 8^{\frac{1}{3}} = (2^3)^{\frac{1}{3}} = 2^{3 \cdot \frac{1}{3}} = 2^1 = 2\]

\[16^{-\frac{3}{4}} = (2^4)^{-\frac{3}{4}} = 2^{4 \cdot (-\frac{3}{4})} = 2^{-3} = \frac{1}{2^3} = \frac{1}{8}\]

\[81^{-\frac{1}{4}} = (3^4)^{-\frac{1}{4}} = 3^{4 \cdot (-\frac{1}{4})} = 3^{-1} = \frac{1}{3}\]

\[(\frac{1}{27})^{\frac{1}{3}} = (\frac{1}{3^3})^{\frac{1}{3}} = (3^{-3})^{\frac{1}{3}} = 3^{-3 \cdot \frac{1}{3}} = 3^{-1} = \frac{1}{3}\]

\[64^{\frac{1}{3}} = (4^3)^{\frac{1}{3}} = 4^{3 \cdot \frac{1}{3}} = 4^1 = 4\]

\[25^{\frac{1}{2}} = (5^2)^{\frac{1}{2}} = 5^{2 \cdot \frac{1}{2}} = 5^1 = 5\]

\[(\sqrt{3})^4 = (3^{\frac{1}{2}})^4 = 3^{\frac{1}{2} \cdot 4} = 3^2 = 9\]

\[(\sqrt{5})^0 = 1\]

\[(\frac{3}{4})^{-1} = \frac{1}{\frac{3}{4}} = \frac{4}{3}\]

\[(\frac{1}{2})^{-4} = (2^{-1})^{-4} = 2^{-1 \cdot (-4)} = 2^4 = 16\]

\[7^{-2} = \frac{1}{7^2} = \frac{1}{49}\]

\[4^{-1} = \frac{1}{4}\]

\[(\frac{2}{5})^3 = \frac{2^3}{5^3} = \frac{8}{125}\]

\[(\frac{3}{4})^2 = \frac{3^2}{4^2} = \frac{9}{16}\]

\[5^0 = 1\]

\[2^3 = 8\]