Выполним действия с дробями:
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$$\frac{1}{3} + \frac{5}{8} =$$
$$\frac{1 \cdot 8}{3 \cdot 8} + \frac{5 \cdot 3}{8 \cdot 3} =$$
$$\frac{8}{24} + \frac{15}{24} =$$
$$\frac{8 + 15}{24} = \frac{23}{24}$$
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$$\frac{4}{5} + \frac{2}{9} =$$
$$\frac{4 \cdot 9}{5 \cdot 9} + \frac{2 \cdot 5}{9 \cdot 5} =$$
$$\frac{36}{45} + \frac{10}{45} =$$
$$\frac{36 + 10}{45} = \frac{46}{45}$$
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$$\frac{6}{7} - \frac{1}{4} =$$
$$\frac{6 \cdot 4}{7 \cdot 4} - \frac{1 \cdot 7}{4 \cdot 7} =$$
$$\frac{24}{28} - \frac{7}{28} =$$
$$\frac{24 - 7}{28} = \frac{17}{28}$$
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$$\frac{7}{8} - \frac{1}{12} =$$
$$\frac{7 \cdot 3}{8 \cdot 3} - \frac{1 \cdot 2}{12 \cdot 2} =$$
$$\frac{21}{24} - \frac{2}{24} =$$
$$\frac{21-2}{24} = \frac{19}{24}$$
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$$\frac{17}{18} + \frac{17}{24} - \frac{5}{8} =$$
$$\frac{17 \cdot 4}{18 \cdot 4} + \frac{17 \cdot 3}{24 \cdot 3} - \frac{5 \cdot 9}{8 \cdot 9} =$$
$$\frac{68}{72} + \frac{51}{72} - \frac{45}{72} =$$
$$\frac{68 + 51 - 45}{72} =$$
$$\frac{119 - 45}{72} = \frac{74}{72} = \frac{37}{36}$$
Ответ: См. решение