\[1 \frac{16}{21} + \frac{4}{7} = 1 \frac{16}{21} + \frac{4 \cdot 3}{7 \cdot 3} = 1 \frac{16}{21} + \frac{12}{21} = 1 \frac{16+12}{21} = 1 \frac{28}{21} = 1 + \frac{28}{21} = 1 + \frac{4}{3} = 1 + 1 \frac{1}{3} = 2 \frac{1}{3}\]
\[\frac{14}{5} = 2 \frac{4}{5}\]
\[3 \frac{5}{24} - (-\frac{1}{3}) = 3 \frac{5}{24} + \frac{1}{3} = 3 \frac{5}{24} + \frac{1 \cdot 8}{3 \cdot 8} = 3 \frac{5}{24} + \frac{8}{24} = 3 \frac{5+8}{24} = 3 \frac{13}{24}\]
Ответ: 1) 2 \frac{1}{3}; 2) 2 \frac{4}{5}; 3) 3 \frac{13}{24}