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МатематикаВопрос:
20 이동. (음) KL= 2/8,526 17 9(93-7594 )50×25 イ
Ответ:
Краткое пояснение: Решаем представленные математические примеры и уравнения.
- \[\left(\frac{17}{15} - \frac{1}{12}\right) \cdot \frac{20}{3} = \left(\frac{17 \cdot 4}{15 \cdot 4} - \frac{1 \cdot 5}{12 \cdot 5}\right) \cdot \frac{20}{3} = \left(\frac{68}{60} - \frac{5}{60}\right) \cdot \frac{20}{3} = \frac{63}{60} \cdot \frac{20}{3} = \frac{63 \cdot 20}{60 \cdot 3} = \frac{63}{3} \cdot \frac{20}{60} = 21 \cdot \frac{1}{3} = 7\]
- 4.526 + 17 = 21.526
- \(\frac{5}{8} - \frac{3}{3} \cdot \frac{2}{7} = \frac{5}{8} - \frac{6}{21} = \frac{5}{8} - \frac{2}{7} = \frac{5 \cdot 7}{8 \cdot 7} - \frac{2 \cdot 8}{7 \cdot 8} = \frac{35}{56} - \frac{16}{56} = \frac{35 - 16}{56} = \frac{19}{56}\)
- \(\frac{1}{9} \cdot \left(15 - \frac{1}{7}\right) = \frac{1}{9} \cdot \left(\frac{15 \cdot 7}{7} - \frac{1}{7}\right) = \frac{1}{9} \cdot \frac{105 - 1}{7} = \frac{1}{9} \cdot \frac{104}{7} = \frac{104}{63}\)
- \(\frac{4}{5} \cdot \frac{3}{75} = \frac{4}{5} \cdot \frac{1}{25} = \frac{4}{125}\)
- \(\frac{5}{15} - \frac{5}{90} = \frac{1}{3} - \frac{1}{18} = \frac{1 \cdot 6}{3 \cdot 6} - \frac{1}{18} = \frac{6}{18} - \frac{1}{18} = \frac{5}{18}\)
- \(1.8 - 0.51:5 = 1.8 - 0.102 = 1.698\)
- \(9 : \left(\frac{19}{10} - 1\right) = 9 : \left(\frac{19}{10} - \frac{10}{10}\right) = 9 : \frac{9}{10} = 9 \cdot \frac{10}{9} = 10\)
- \(9 \cdot (4.3 - 3.3) \cdot 0.4 = 9 \cdot 1 \cdot 0.4 = 3.6\)
- \(\frac{3}{8} + 5 \cdot \frac{5}{7} = \frac{3}{8} + \frac{25}{7} = \frac{3 \cdot 7}{8 \cdot 7} + \frac{25 \cdot 8}{7 \cdot 8} = \frac{21}{56} + \frac{200}{56} = \frac{221}{56}\)
- \(50 - 13 \cdot x = 25\) \(-13 \cdot x = 25 - 50\) \(-13 \cdot x = -25\) \(x = \frac{-25}{-13}\) \(x = \frac{25}{13}\)
- \(x + 5 \cdot (3 + 3) = 5\) \(x + 5 \cdot 6 = 5\) \(x + 30 = 5\) \(x = 5 - 30\) \(x = -25\)
- \(2x - 3(x+3) = -5\) \(2x - 3x - 9 = -5\) \(-x = -5 + 9\) \(-x = 4\) \(x = -4\)
- \(2(5 + x) = -15\) \(10 + 2x = -15\) \(2x = -15 - 10\) \(2x = -25\) \(x = \frac{-25}{2}\)
Ответ: Решения выше
