\[13 \frac{17}{18} - 6 \frac{5}{18} = (13 - 6) + (\frac{17}{18} - \frac{5}{18}) = 7 + \frac{12}{18} = 7 \frac{2}{3}\]
\[8 \frac{5}{11} - 6 \frac{5}{11} = (8 - 6) + (\frac{5}{11} - \frac{5}{11}) = 2 + 0 = 2\]
\[17 \frac{10}{18} - 10 \frac{10}{18} = (17 - 10) + (\frac{10}{18} - \frac{10}{18}) = 7 + 0 = 7\]
\[10 \frac{8}{9} - \frac{9}{9} = 10 \frac{8}{9} - 1 = 9 \frac{8}{9}\]
\[13 \frac{3}{24} + 11 \frac{11}{24} = (13 + 11) + (\frac{3}{24} + \frac{11}{24}) = 24 + \frac{14}{24} = 24 \frac{7}{12}\]
\[5 \frac{2}{14} + 2 \frac{3}{14} = (5 + 2) + (\frac{2}{14} + \frac{3}{14}) = 7 + \frac{5}{14} = 7 \frac{5}{14}\]
\[5 \frac{4}{9} + \frac{6}{9} = 5 + (\frac{4}{9} + \frac{6}{9}) = 5 + \frac{10}{9} = 5 + 1 \frac{1}{9} = 6 \frac{1}{9}\]
\[7 \frac{3}{8} - 2 \frac{1}{8} = (7 - 2) + (\frac{3}{8} - \frac{1}{8}) = 5 + \frac{2}{8} = 5 \frac{1}{4}\]
\[10 \frac{3}{13} + 5 \frac{5}{13} = (10 + 5) + (\frac{3}{13} + \frac{5}{13}) = 15 + \frac{8}{13} = 15 \frac{8}{13}\]
\[17 \frac{9}{10} + 50 \frac{7}{10} = (17 + 50) + (\frac{9}{10} + \frac{7}{10}) = 67 + \frac{16}{10} = 67 + 1 \frac{6}{10} = 68 \frac{3}{5}\]
\[5 \frac{8}{9} - 3 = (5 - 3) + \frac{8}{9} = 2 + \frac{8}{9} = 2 \frac{8}{9}\]
\[10 \frac{5}{14} - 8 \frac{3}{14} = (10 - 8) + (\frac{5}{14} - \frac{3}{14}) = 2 + \frac{2}{14} = 2 \frac{1}{7}\]
\[\frac{3}{4} + \frac{5}{7} = \frac{3 \cdot 7 + 5 \cdot 4}{4 \cdot 7} = \frac{21 + 20}{28} = \frac{41}{28} = 1 \frac{13}{28}\]
\[\frac{17}{24} + \frac{25}{36} = \frac{17 \cdot 3 + 25 \cdot 2}{72} = \frac{51 + 50}{72} = \frac{101}{72} = 1 \frac{29}{72}\]
\[\frac{11}{18} - \frac{5}{12} = \frac{11 \cdot 2 - 5 \cdot 3}{36} = \frac{22 - 15}{36} = \frac{7}{36}\]
\[\frac{3}{5} - \frac{5}{13} = \frac{3 \cdot 13 - 5 \cdot 5}{65} = \frac{39 - 25}{65} = \frac{14}{65}\]
\[\frac{1}{14} + \frac{5}{12} = \frac{1 \cdot 6 + 5 \cdot 7}{84} = \frac{6 + 35}{84} = \frac{41}{84}\]
\[\frac{7}{8} - \frac{1}{3} = \frac{7 \cdot 3 - 1 \cdot 8}{24} = \frac{21 - 8}{24} = \frac{13}{24}\]
\[2 \frac{1}{3} + 1 \frac{1}{2} = \frac{7}{3} + \frac{3}{2} = \frac{7 \cdot 2 + 3 \cdot 3}{6} = \frac{14 + 9}{6} = \frac{23}{6} = 3 \frac{5}{6}\]
\[\frac{7}{12} - \frac{1}{18} = \frac{7 \cdot 3 - 1 \cdot 2}{36} = \frac{21 - 2}{36} = \frac{19}{36}\]
\[1 \frac{17}{100} - \frac{9}{10} = \frac{117}{100} - \frac{90}{100} = \frac{27}{100}\]
\[\frac{3}{7} > \frac{2}{5}\]
\[\frac{2}{5} < \frac{3}{11}\]
\[\frac{7}{8} > \frac{3}{4}\]
\[\frac{3}{10} < \frac{7}{12}\]
\[\frac{2}{3} > \frac{7}{11}\]
\[\frac{1}{4} < \frac{3}{16}\]
\[\frac{7}{5} > \frac{8}{12}\]
\[\frac{12}{24} = \frac{8}{16}\]
\[1 \frac{3}{8} : \frac{1}{7} = \frac{11}{8} \cdot 7 = \frac{77}{8} = 9 \frac{5}{8}\]
\[5 \frac{3}{24} : 10 = \frac{123}{24} : 10 = \frac{41}{80}\]
\[4 \frac{1}{15} : 3 = \frac{61}{15} : 3 = \frac{61}{45} = 1 \frac{16}{45}\]
\[3 \frac{4}{9} : \frac{2}{27} = \frac{31}{9} \cdot \frac{27}{2} = \frac{31 \cdot 3}{2} = \frac{93}{2} = 46 \frac{1}{2}\]
\[8 \frac{4}{25} : \frac{8}{15} = \frac{204}{25} \cdot \frac{15}{8} = \frac{204 \cdot 3}{5 \cdot 8} = \frac{51 \cdot 3}{5 \cdot 2} = \frac{153}{10} = 15 \frac{3}{10}\]
\[10 : 17 \frac{1}{5} = 10 : \frac{86}{5} = 10 \cdot \frac{5}{86} = \frac{50}{86} = \frac{25}{43}\]
\[5 : 7 \frac{1}{2} = 5 : \frac{15}{2} = 5 \cdot \frac{2}{15} = \frac{10}{15} = \frac{2}{3}\]
\[1 \frac{3}{18} : 1 \frac{8}{15} = \frac{21}{18} : \frac{23}{15} = \frac{21}{18} \cdot \frac{15}{23} = \frac{7 \cdot 5}{6 \cdot 23} = \frac{35}{46}\]
\[\frac{8}{10} = \frac{4}{5}\]
\[\frac{25}{75} = \frac{1}{3}\]
\[\frac{10}{25} = \frac{2}{5}\]
\[\frac{18}{24} = \frac{3}{4}\]
\[\frac{14}{16} = \frac{7}{8}\]
\[\frac{3}{63} = \frac{1}{21}\]
\[\frac{4}{96} = \frac{1}{24}\]
\[\frac{48}{72} = \frac{2}{3}\]
\[\frac{33}{77} = \frac{3}{7}\]
\[\frac{12}{30} = \frac{2}{5}\]
\[21 \cdot (\frac{13}{24} - \frac{7}{12}) \cdot \frac{1}{6} = 21 \cdot (\frac{13 - 14}{24}) \cdot \frac{1}{6} = 21 \cdot (\frac{-1}{24}) \cdot \frac{1}{6} = \frac{-7}{48}\]
\[\frac{29}{7} \cdot (\frac{2}{7} + \frac{3}{4}) = \frac{29}{7} \cdot (\frac{8 + 21}{28}) = \frac{29}{7} \cdot \frac{29}{28} = \frac{841}{196} = 4 \frac{57}{196}\]
\[3 : \frac{1}{2} + 5 : 1 \frac{1}{4} = 3 \cdot 2 + 5 : \frac{5}{4} = 6 + 5 \cdot \frac{4}{5} = 6 + 4 = 10\]
\[(\frac{2}{16} - \frac{1}{14}) \cdot 28 = (\frac{1}{8} - \frac{1}{14}) \cdot 28 = (\frac{7 - 4}{56}) \cdot 28 = \frac{3}{56} \cdot 28 = \frac{3}{2} = 1 \frac{1}{2}\]
\[13 \frac{2}{5} + 11 \frac{1}{3} : \frac{9}{5} = \frac{67}{5} + \frac{34}{3} \cdot \frac{5}{9} = \frac{67}{5} + \frac{34 \cdot 5}{3 \cdot 9} = \frac{67}{5} + \frac{170}{27} = \frac{67 \cdot 27 + 170 \cdot 5}{135} = \frac{1809 + 850}{135} = \frac{2659}{135} = 19 \frac{104}{135}\]
\[\frac{4}{2} - \frac{1}{9} : 8 - 5 \cdot \frac{1}{10} + \frac{2}{3} = 2 - \frac{1}{9 \cdot 8} - \frac{1}{2} + \frac{2}{3} = 2 - \frac{1}{72} - \frac{1}{2} + \frac{2}{3} = \frac{2 \cdot 72 - 1 - 36 + 48}{72} = \frac{144 - 1 - 36 + 48}{72} = \frac{155}{72} = 2 \frac{11}{72}\]
Ответ: Решения выше