№1. Решите уравнения: 11,4b - (2,7b + 3,2b) + 2,35 = 6,2; 15d - (12,1d - 0,7d) + 5,6 = 20; $$3x+\frac{1}{6}-(3\frac{1}{2}x-1\frac{1}{4}x)= 4\frac{2}{3}$$

Решим уравнения:

1) $$11,4b - (2,7b + 3,2b) + 2,35 = 6,2$$

$$11,4b - 5,9b + 2,35 = 6,2$$

$$5,5b = 6,2 - 2,35$$

$$5,5b = 3,85$$

$$b = \frac{3,85}{5,5}$$

$$b = 0,7$$

2) $$15d - (12,1d - 0,7d) + 5,6 = 20$$

$$15d - 11,4d + 5,6 = 20$$

$$3,6d = 20 - 5,6$$

$$3,6d = 14,4$$

$$d = \frac{14,4}{3,6}$$

$$d = 4$$

3) $$3x+\frac{1}{6}-(3\frac{1}{2}x-1\frac{1}{4}x)= 4\frac{2}{3}$$

$$3x+\frac{1}{6}-(\frac{7}{2}x-\frac{5}{4}x)= \frac{14}{3}$$

$$3x+\frac{1}{6}-(\frac{14}{4}x-\frac{5}{4}x)= \frac{14}{3}$$

$$3x+\frac{1}{6}-\frac{9}{4}x= \frac{14}{3}$$

$$3x-\frac{9}{4}x= \frac{14}{3}-\frac{1}{6}$$

$$\frac{12x-9x}{4}= \frac{28-1}{6}$$

$$\frac{3}{4}x= \frac{27}{6}$$

$$x= \frac{27}{6} \div \frac{3}{4}$$

$$x= \frac{27}{6} \times \frac{4}{3}$$

$$x= \frac{9}{3} \times \frac{4}{2}$$

$$x= 3 \times 2$$

$$x=6$$

Ответ: b = 0,7; d = 4; x = 6.