№1 Вычислить по действиям 1. \(7 \cdot 6\frac{1}{22} + 69\frac{27}{77} - 4 : 1\frac{1}{3} - \frac{1}{14} - 55\frac{1}{3};\) 2. \(76,025 + 23\frac{97}{120} - (\frac{37}{39} + 0,2 \cdot 3\frac{22}{41} : \frac{3}{41}) : 10\frac{8}{13} : 82\).

1. \(7 \cdot 6\frac{1}{22} + 69\frac{27}{77} - 4 : 1\frac{1}{3} - \frac{1}{14} - 55\frac{1}{3} = 7 \cdot \frac{133}{22} + \frac{5340}{77} - 4 : \frac{4}{3} - \frac{1}{14} - \frac{166}{3} = \frac{931}{22} + \frac{5340}{77} - 4 \cdot \frac{3}{4} - \frac{1}{14} - \frac{166}{3} = \frac{931}{22} + \frac{5340}{77} - 3 - \frac{1}{14} - \frac{166}{3} = \frac{28863 + 10680 - 1386 - 33 - 12188}{462} = \frac{40143 - 13607}{462} = \frac{26536}{462} = \frac{13268}{231} = 57\frac{41}{231}\) 2. \(76,025 + 23\frac{97}{120} - (\frac{37}{39} + 0,2 \cdot 3\frac{22}{41} : \frac{3}{41}) : 10\frac{8}{13} : 82 = 76,025 + \frac{2857}{120} - (\frac{37}{39} + \frac{1}{5} \cdot \frac{145}{41} : \frac{3}{41}) : \frac{138}{13} : 82 = 76,025 + \frac{2857}{120} - (\frac{37}{39} + \frac{1}{5} \cdot \frac{145}{41} \cdot \frac{41}{3}) : \frac{138}{13} : 82 = 76,025 + \frac{2857}{120} - (\frac{37}{39} + \frac{29}{3}) : \frac{138}{13} : 82 = 76,025 + \frac{2857}{120} - (\frac{37+377}{39}) : \frac{138}{13} : 82 = 76,025 + \frac{2857}{120} - \frac{414}{39} : \frac{138}{13} : 82 = 76,025 + \frac{2857}{120} - \frac{414}{39} \cdot \frac{13}{138} : 82 = 76,025 + \frac{2857}{120} - \frac{3}{3} : 82 = 76,025 + \frac{2857}{120} - 1 : 82 = 76,025 + \frac{2857}{120} - \frac{1}{82} = 76,025 + 23,808(3) - 0,012195 = 99,8333 - 0,012195 = 99,821138 \) Ответ: 1. \(57\frac{41}{231}\); 2. \(99,821138\)