Решение №3
1) \(-14 + 9 = -5\)
2) \(28 + (-5) = 28 - 5 = 23\)
3) \(-21 - 16 = -37\)
4) \(-19 - (-81) = -19 + 81 = 62\)
5) \(-2.5 - 1.9 = -4.4\)
6) \(-\frac{3}{16} + \frac{5}{12} = -\frac{3 \cdot 3}{16 \cdot 3} + \frac{5 \cdot 4}{12 \cdot 4} = -\frac{9}{48} + \frac{20}{48} = \frac{11}{48}\)
7) \(-\frac{10}{11} - (-\frac{10}{11}) = -\frac{10}{11} + \frac{10}{11} = 0\)
8) \(1\frac{2}{9} + (-\frac{11}{27}) = \frac{11}{9} - \frac{11}{27} = \frac{11 \cdot 3}{9 \cdot 3} - \frac{11}{27} = \frac{33}{27} - \frac{11}{27} = \frac{22}{27}\)
Решение №4
1) \(21 + x = 8\)
\(x = 8 - 21\)
\(x = -13\)
2) \(x - 4.5 = -8.8\)
\(x = -8.8 + 4.5\)
\(x = -4.3\)
3) \(-11.8 - x = -4.6\)
\(-x = -4.6 + 11.8\)
\(-x = 7.2\)
\(x = -7.2\)
Решение №5
1) \(\frac{13}{30} - (-\frac{1}{6}) + (-\frac{7}{10}) - \frac{11}{15} = \frac{13}{30} + \frac{1}{6} - \frac{7}{10} - \frac{11}{15} = \frac{13}{30} + \frac{5}{30} - \frac{21}{30} - \frac{22}{30} = \frac{13 + 5 - 21 - 22}{30} = \frac{-25}{30} = -\frac{5}{6}\)
2) \(-(-\frac{1}{2}) - \frac{47}{50} - \frac{2}{5} + (-\frac{3}{10}) = \frac{1}{2} - \frac{47}{50} - \frac{2}{5} - \frac{3}{10} = \frac{25}{50} - \frac{47}{50} - \frac{20}{50} - \frac{15}{50} = \frac{25 - 47 - 20 - 15}{50} = \frac{-57}{50} = -1\frac{7}{50}\)
3) \(-\frac{23}{44} - \frac{1}{2} + \frac{3}{4} + \frac{31}{88} + \frac{9}{11} = -\frac{46}{88} - \frac{44}{88} + \frac{66}{88} + \frac{31}{88} + \frac{72}{88} = \frac{-46 - 44 + 66 + 31 + 72}{88} = \frac{79}{88}\)
4) \(-\frac{13}{46} - \frac{3}{4} - \frac{61}{120} + \frac{11}{30} - \frac{7}{12} = -\frac{13 \cdot 60}{46 \cdot 60} - \frac{3 \cdot 345}{4 \cdot 345} - \frac{61 \cdot 23}{120 \cdot 23} + \frac{11 \cdot 92}{30 \cdot 92} - \frac{7 \cdot 115}{12 \cdot 115} = \frac{-780 - 1035 - 1403 + 1012 - 805}{1380} = \frac{-3000 - 1035 - 1403 + 1012 - 805 + 217}{1380} = -\frac{3391}{1380} \approx -2.457\)
Ответ: Задания выполнены!
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