№1. Выполните сложение дробей:
- \frac{2}{5} + \frac{1}{10} = \frac{2 \cdot 2}{5 \cdot 2} + \frac{1}{10} = \frac{4}{10} + \frac{1}{10} = \frac{4+1}{10} = \frac{5}{10} = \frac{1}{2}
- \frac{5}{6} + \frac{2}{3} = \frac{5}{6} + \frac{2 \cdot 2}{3 \cdot 2} = \frac{5}{6} + \frac{4}{6} = \frac{5+4}{6} = \frac{9}{6} = \frac{3}{2} = 1\frac{1}{2}
- \frac{3}{4} + \frac{7}{12} = \frac{3 \cdot 3}{4 \cdot 3} + \frac{7}{12} = \frac{9}{12} + \frac{7}{12} = \frac{9+7}{12} = \frac{16}{12} = \frac{4}{3} = 1\frac{1}{3}
- \frac{2}{15} + \frac{4}{5} = \frac{2}{15} + \frac{4 \cdot 3}{5 \cdot 3} = \frac{2}{15} + \frac{12}{15} = \frac{2+12}{15} = \frac{14}{15}
- \frac{5}{7} + \frac{3}{14} = \frac{5 \cdot 2}{7 \cdot 2} + \frac{3}{14} = \frac{10}{14} + \frac{3}{14} = \frac{10+3}{14} = \frac{13}{14}
- \frac{3}{11} + \frac{6}{55} = \frac{3 \cdot 5}{11 \cdot 5} + \frac{6}{55} = \frac{15}{55} + \frac{6}{55} = \frac{15+6}{55} = \frac{21}{55}
- \frac{1}{6} + \frac{1}{9} = \frac{1 \cdot 3}{6 \cdot 3} + \frac{1 \cdot 2}{9 \cdot 2} = \frac{3}{18} + \frac{2}{18} = \frac{3+2}{18} = \frac{5}{18}
- \frac{1}{10} + \frac{1}{15} = \frac{1 \cdot 3}{10 \cdot 3} + \frac{1 \cdot 2}{15 \cdot 2} = \frac{3}{30} + \frac{2}{30} = \frac{3+2}{30} = \frac{5}{30} = \frac{1}{6}
- \frac{2}{8} + \frac{1}{12} = \frac{2 \cdot 3}{8 \cdot 3} + \frac{1 \cdot 2}{12 \cdot 2} = \frac{6}{24} + \frac{2}{24} = \frac{6+2}{24} = \frac{8}{24} = \frac{1}{3}
- \frac{1}{9} + \frac{1}{2} = \frac{1 \cdot 2}{9 \cdot 2} + \frac{1 \cdot 9}{2 \cdot 9} = \frac{2}{18} + \frac{9}{18} = \frac{2+9}{18} = \frac{11}{18}
Ответ: 1) \frac{1}{2}; 2) 1\frac{1}{2}; 3) 1\frac{1}{3}; 4) \frac{14}{15}; 5) \frac{13}{14}; 6) \frac{21}{55}; 7) \frac{5}{18}; 8) \frac{1}{6}; 9) \frac{1}{3}; 10) \frac{11}{18}