01.7. а) \(\left(4\frac{1}{3}+3\frac{1}{5}\right):113\); б) \(\left(6-7\frac{1}{8}\right)\cdot\left(2\frac{2}{9}+2\frac{2}{3}\right)\).

а)

\(4\frac{1}{3}=\frac{13}{3}\), \(3\frac{1}{5}=\frac{16}{5}\).

\(\left(\frac{13}{3}+\frac{16}{5}\right):113=\left(\frac{65}{15}+\frac{48}{15}\right):113=\frac{113}{15}:113=\frac{113}{15}\cdot\frac{1}{113}=\frac{1}{15}\).

б)

\(6-7\frac{1}{8}=\frac{48}{8}-\frac{57}{8}=-\frac{9}{8}\).

\(2\frac{2}{9}+2\frac{2}{3}=\frac{20}{9}+\frac{8}{3}=\frac{20}{9}+\frac{24}{9}=\frac{44}{9}\).

\(\left(-\frac{9}{8}\right)\cdot\frac{44}{9}=-\frac{44}{8}=-\frac{11}{2}=-5\frac{1}{2}\).

Ответ: а) \(\frac{1}{15}\); б) \(-5\frac{1}{2}\).