1.1. Вычислите: 1) \((\frac{2}{47}-\frac{3}{53}):0,2\); 2) \(\frac{1-10^{-4}}{99}:\frac{0,16}{25}\); 3) \(0,3^4-0,08^2-\frac{1}{125}+\frac{3}{25}-\frac{3}{5}+1\).

1. \(\left(\frac{2}{47}-\frac{3}{53}\right):0,2=\left(\frac{106}{2491}-\frac{141}{2491}\right):\frac{1}{5}=\frac{-35}{2491}\cdot5=\frac{-175}{2491}.\)
2. \(\frac{1-10^{-4}}{99}:\frac{0,16}{25}=\frac{1-0,0001}{99}:\frac{4}{625}=\frac{0,9999}{99}\cdot\frac{625}{4}=\frac{101}{10000}\cdot\frac{625}{4}=\frac{101}{64}.\)
3. \(0,3^4-0,08^2-\frac{1}{125}+\frac{3}{25}-\frac{3}{5}+1=0,0081-0,0064-0,008+0,12-0,6+1=0,5137.\)

Ответ: 1) \(-\frac{175}{2491}\); 2) \(\frac{101}{64}\); 3) \(0,5137\).