Ответ:

  1. \(\frac{7}{8}-\frac{5}{6}\cdot\frac{9}{20}=\frac{7}{8}-\frac{3}{8}=\frac{1}{2}\).
  2. \(\frac{2}{9}+\frac{4}{7}\cdot\frac{9}{28}=\frac{2}{9}+\frac{9}{49}=\frac{98}{441}+\frac{81}{441}=\frac{179}{441}\).
  3. \(4\frac{1}{6}\cdot\frac{5}{2}+\frac{1}{3}=\frac{25}{6}\cdot\frac{5}{2}+\frac{1}{3}=\frac{125}{12}+\frac{4}{12}=\frac{129}{12}=10\frac{3}{4}\).
  4. \(1-\frac{4}{5}\cdot2\frac{2}{9}=1-\frac{4}{5}\cdot\frac{20}{9}=1-\frac{16}{9}=-\frac{7}{9}\).
  5. \(\frac{22}{3}:\frac{11}{48}\cdot\frac{5}{8}=\frac{22}{3}\cdot\frac{48}{11}\cdot\frac{5}{8}=20\).
  6. \(2,64:2,2-0,5=1,2-0,5=0,7\).
  7. \(-4,9+4,81:1,3=-4,9+3,7=-1,2\).
  8. \((2,6-8,4):2,5=-5,8:2,5=-2,32\).

Ответ: а) \(\frac{1}{2}\); б) \(\frac{179}{441}\); в) \(10\frac{3}{4}\); г) \(-\frac{7}{9}\); д) 20; е) 0,7; ж) −1,2; з) −2,32.