Решение:
- \(2\sqrt{7} = \sqrt{2^2} \cdot \sqrt{7} = \sqrt{4 \cdot 7} = \sqrt{28}\)
- \(3\sqrt{11} = \sqrt{3^2} \cdot \sqrt{11} = \sqrt{9 \cdot 11} = \sqrt{99}\)
- \(0.2\sqrt{5} = \sqrt{0.2^2} \cdot \sqrt{5} = \sqrt{0.04 \cdot 5} = \sqrt{0.2}\)
- \(\frac{1}{3}\sqrt{54} = \sqrt{\left(\frac{1}{3}\right)^2} \cdot \sqrt{54} = \sqrt{\frac{1}{9} \cdot 54} = \sqrt{\frac{54}{9}} = \sqrt{6}\)
Ответ: 1) \(\sqrt{28}\), 2) \(\sqrt{99}\), 3) \(\sqrt{0.2}\), 4) \(\sqrt{6}\).