Вопрос:
1) 24 − 7 5/6 − 6 5/6 − 4 1/6; 2) 19 3/10 − 9 9/10 + 7 1/10 − 1 5/10; 3) 45 − 8 13/20 + 9 14/20 − 39 19/20; 4) 5 29/90 + (17 2/3 + 4 3/8 − 19 5/9 − (6 1/36 − 5 3/16)); 5) (3/19 + 5/38) · 57 + (7/36 + 5/54) · 18 − 3 · (3/4 + 5/6); 6) 6/7 · 7/8 · 9/10 · 8/9 · 10/11; 7) 1 1/24 · 3 1/8 · 8/15 · 3 7/9 · 1 15/17; 8) ((1 2/3)^2 − 1 1/2) · 4 2/23 + 21/23 : (2 5/6 − 2 10/12); 9) 70 : (5/8 + 5/6) + (3 1/9 − 1/3) : (3 1/3); 10) (3 1/2 : 4 2/3 + 4 2/3 : 3 1/2) · 4 4/5; 11) (27 3/8 − 21 7/20) / ((3 4/7 − 1 23/28) − (1 47/65 − 29/130)) Ответ: \(24-7\frac56-6\frac56-4\frac16=24-18\frac56=5\frac16\). Ответ: \(5\frac16\) . \(19\frac3{10}-9\frac9{10}+7\frac1{10}-1\frac5{10}=15\). Ответ: \(15\) . \(45-8\frac{13}{20}+9\frac{14}{20}-39\frac{19}{20}=5\). Ответ: \(5\) . \(5\frac{29}{90}+\left(17\frac23+4\frac38-19\frac59-\left(6\frac1{36}-5\frac3{16}\right)\right)=\frac{443}{1440}=\frac{443}{1440}\). Ответ: \(\frac{443}{1440}\) . \(\left(\frac3{19}+\frac5{38}\right)\cdot57+\left(\frac7{36}+\frac5{54}\right)\cdot18-3\left(\frac34+\frac56\right)=\frac{11}{2}\cdot3+\frac{31}{108}\cdot18-\frac{19}{4}=\frac{65}{12}\). Ответ: \(\frac{65}{12}\) . \(\frac67\cdot\frac78\cdot\frac9{10}\cdot\frac89\cdot\frac{10}{11}=\frac6{11}\). Ответ: \(\frac6{11}\) . \(1\frac1{24}\cdot3\frac18\cdot\frac8{15}\cdot3\frac79\cdot1\frac{15}{17}=\frac{25}{24}\cdot\frac{25}{8}\cdot\frac8{15}\cdot\frac{34}{9}\cdot\frac{32}{17}=\frac{4000}{81}\). Ответ: \(\frac{4000}{81}\) . \(\left(\left(1\frac23\right)^2-1\frac12\right)\cdot4\frac2{23}+\frac{21}{23}:\left(2\frac56-2\frac{10}{12}\right)=\frac{37}{18}\cdot\frac{94}{23}+\frac{21}{23}:\frac12=\frac{583}{69}\). Ответ: \(\frac{583}{69}\) . \(70:\left(\frac58+\frac56\right)+\left(3\frac19-\frac13\right):3\frac13=70:\frac{35}{24}+\frac{25}{9}:\frac{10}{3}=48+\frac56=48\frac56\). Ответ: \(48\frac56\) . \(\left(3\frac12:4\frac23+4\frac23:3\frac12\right)\cdot4\frac45=\left(\frac34+\frac43\right)\cdot\frac{24}{5}=\frac{125}{12}\). Ответ: \(\frac{125}{12}\) . \(27\frac38-21\frac7{20}=5\frac{31}{40}\). В знаменателе: \(3\frac47-1\frac{23}{28}=2\frac5{28}\), \(1\frac{47}{65}-\frac{29}{130}=1\frac{13}{26}=1\frac12\), поэтому знаменатель равен \(\frac{15}{28}\). Тогда \(5\frac{31}{40}:\frac{15}{28}=\frac{599}{40}\cdot\frac{28}{15}=\frac{4193}{150}\). Ответ: \(\frac{4193}{150}=27\frac{143}{150}\) . 👍 👎