1) 248:2-124+963:3-321+4 2) 11 \(\frac{1}{5}\) \(\cdot\) \(\frac{4}{6} - \frac{2}{5}\) + 1 \(\frac{11}{20}\) 3) 3 \(\frac{1}{7}\) : 3 \(\frac{2}{7}\) \(\cdot\) \(\frac{1}{4} - \frac{27}{55}\) 4) \(\frac{(17-12) \cdot 8}{15 \cdot 16}\) 5) \(\frac{(25-9) \cdot 25}{45 \cdot (38-22)}\) 6) \(\frac{25}{45}\) \(\cdot\) (25-9) \(\cdot\) (38-22) 7) \(\frac{1}{4}\) + 2,7 8) 29-17

Решение:

1. \( 248:2-124+963:3-321+4 = 124 - 124 + 321 - 321 + 4 = 4 \)
2. \( 1 \frac{1}{5} \cdot (\frac{4}{6} - \frac{2}{5}) + 1 \frac{11}{20} = \frac{6}{5} \cdot (\frac{2}{3} - \frac{2}{5}) + \frac{31}{20} = \frac{6}{5} \cdot (\frac{10-6}{15}) + \frac{31}{20} = \frac{6}{5} \cdot \frac{4}{15} + \frac{31}{20} = \frac{24}{75} + \frac{31}{20} = \frac{8}{25} + \frac{31}{20} = \frac{32+31}{100} = \frac{63}{100} = 0.63 \)
3. \( 3 \frac{1}{7} : 3 \frac{2}{7} \cdot (\frac{1}{4} - \frac{27}{55}) = \frac{22}{7} : \frac{23}{7} \cdot (\frac{55-108}{220}) = \frac{22}{7} \cdot \frac{7}{23} \cdot (-\frac{53}{220}) = \frac{22}{23} \cdot (-\frac{53}{220}) = \frac{1}{23} \cdot (-\frac{53}{10}) = -\frac{53}{230} \)
4. \( \frac{(17-12) \cdot 8}{15 \cdot 16} = \frac{5 \cdot 8}{15 \cdot 16} = \frac{40}{240} = \frac{1}{6} \)
5. \( \frac{(25-9) \cdot 25}{45 \cdot (38-22)} = \frac{16 \cdot 25}{45 \cdot 16} = \frac{25}{45} = \frac{5}{9} \)
6. \( \frac{25}{45} \cdot (25-9) \cdot (38-22) = \frac{5}{9} \cdot 16 \cdot 16 = \frac{5 \cdot 256}{9} = \frac{1280}{9} \)
7. \( \frac{1}{4} + 2,7 = 0,25 + 2,7 = 2,95 \)
8. \( 29-17=12 \)

Ответ: 1) 4; 2) 0.63; 3) -53/230; 4) 1/6; 5) 5/9; 6) 1280/9; 7) 2.95; 8) 12.