Вопрос:

1) 2x + 3(2x + 7) = 37; 2) 5x + 2(3x + 4) = 96; 3) 5 - 3x - 2(4x - 1) = 40; 4) 7 - 2x - 3(5x - 2) = 47.

Ответ:

Решение:

  1. \( 2x + 3(2x + 7) = 37 \)
    \( 2x + 6x + 21 = 37 \)
    \( 8x = 37 - 21 \)
    \( 8x = 16 \)
    \( x = \frac{16}{8} = 2 \)
  2. \( 5x + 2(3x + 4) = 96 \)
    \( 5x + 6x + 8 = 96 \)
    \( 11x = 96 - 8 \)
    \( 11x = 88 \)
    \( x = \frac{88}{11} = 8 \)
  3. \( 5 - 3x - 2(4x - 1) = 40 \)
    \( 5 - 3x - 8x + 2 = 40 \)
    \( 7 - 11x = 40 \)
    \( -11x = 40 - 7 \)
    \( -11x = 33 \)
    \( x = \frac{33}{-11} = -3 \)
  4. \( 7 - 2x - 3(5x - 2) = 47 \)
    \( 7 - 2x - 15x + 6 = 47 \)
    \( 13 - 17x = 47 \)
    \( -17x = 47 - 13 \)
    \( -17x = 34 \)
    \( x = \frac{34}{-17} = -2 \)

Ответ: 1) x = 2; 2) x = 8; 3) x = -3; 4) x = -2.

Подать жалобу Правообладателю