Вопрос:
1) a) 11 + 2x = 55 + 3x;
б) -15 - 3x = -7x + 45;
в) -3x - 17 = 8x - 105.
2) a) 2(2 + y) = 19 - 3y;
б) (4 - c) + 2(c - 3) = -13;
в) -3(3b + 1) - 12 = 12.
4) 6,3-x / 2 = 3,5+x / 6
5) 3x / 16 + x / 3 = 1 / 8
Ответ:
Решение уравнений:
- 1)
- a)\[ 11 + 2x = 55 + 3x \]\[ 2x - 3x = 55 - 11 \]\[ -x = 44 \]\[ x = -44 \]
- б)\[ -15 - 3x = -7x + 45 \]\[ -3x + 7x = 45 + 15 \]\[ 4x = 60 \]\[ x = 15 \]
- в)\[ -3x - 17 = 8x - 105 \]\[ -3x - 8x = -105 + 17 \]\[ -11x = -88 \]\[ x = 8 \]
- 2)
- a)\[ 2(2 + y) = 19 - 3y \]\[ 4 + 2y = 19 - 3y \]\[ 2y + 3y = 19 - 4 \]\[ 5y = 15 \]\[ y = 3 \]
- б)\[ (4 - c) + 2(c - 3) = -13 \]\[ 4 - c + 2c - 6 = -13 \]\[ c - 2 = -13 \]\[ c = -13 + 2 \]\[ c = -11 \]
- в)\[ -3(3b + 1) - 12 = 12 \]\[ -9b - 3 - 12 = 12 \]\[ -9b - 15 = 12 \]\[ -9b = 12 + 15 \]\[ -9b = 27 \]\[ b = -3 \]
4)\[ \frac{6.3-x}{2} = \frac{3.5+x}{6} \]\[ 6(6.3 - x) = 2(3.5 + x) \]\[ 37.8 - 6x = 7 + 2x \]\[ 37.8 - 7 = 2x + 6x \]\[ 30.8 = 8x \]\[ x = \frac{30.8}{8} \]\[ x = 3.85 \]5)\[ \frac{3x}{16} + \frac{x}{3} = \frac{1}{8} \]\[ \frac{9x + 16x}{48} = \frac{1}{8} \]\[ \frac{25x}{48} = \frac{1}{8} \]\[ 25x \times 8 = 48 \]\[ 200x = 48 \]\[ x = \frac{48}{200} \]\[ x = \frac{6}{25} \]