1. а) 3х = 15; 6) 4x - 2 = 2x + 6; в) 11 + 5x = 55 + 3x; г) - 8x - 17 = 3x - 105.

Решение:

1. а)\[ 3x = 15 \]\[ x = \frac{15}{3} \]\[ x = 5 \]
2. б)\[ 4x - 2 = 2x + 6 \]\[ 4x - 2x = 6 + 2 \]\[ 2x = 8 \]\[ x = \frac{8}{2} \]\[ x = 4 \]
3. в)\[ 11 + 5x = 55 + 3x \]\[ 5x - 3x = 55 - 11 \]\[ 2x = 44 \]\[ x = \frac{44}{2} \]\[ x = 22 \]
4. г)\[ -8x - 17 = 3x - 105 \]\[ -17 + 105 = 3x + 8x \]\[ 88 = 11x \]\[ x = \frac{88}{11} \]\[ x = 8 \]

Ответ: а) 5; б) 4; в) 22; г) 8.