Решение:
1. Решите уравнение:
- а) 3x + 2 = 0
\( 3x = -2 \)
\( x = -\frac{2}{3} \) - б) 3 - 5x = 0
\( -5x = -3 \)
\( x = \frac{-3}{-5} = \frac{3}{5} \) - в) 0,6х + 1,8 = 0
\( 0,6x = -1,8 \)
\( x = \frac{-1,8}{0,6} = -3 \) - г) 7 - 0,7x = 0
\( -0,7x = -7 \)
\( x = \frac{-7}{-0,7} = 10 \) - 2. а) 8x - 5 = x - 40
\( 8x - x = -40 + 5 \)
\( 7x = -35 \)
\( x = -5 \) - б) 7t + 21 = t - 3
\( 7t - t = -3 - 21 \)
\( 6t = -24 \)
\( t = -4 \) - в) 9 + 13y = 35 + 26y
\( 13y - 26y = 35 - 9 \)
\( -13y = 26 \)
\( y = -2 \) - г) 0,3p - 5 = 6 - 0,7p
\( 0,3p + 0,7p = 6 + 5 \)
\( p = 11 \) - д) 8,31k - 71 = 1,11k + 1
\( 8,31k - 1,11k = 1 + 71 \)
\( 7,2k = 72 \)
\( k = 10 \) - е) 9c + 2,65 = 36,85 - 9c
\( 9c + 9c = 36,85 - 2,65 \)
\( 18c = 34,2 \)
\( c = \frac{34,2}{18} = 1,9 \) - 3. а) 6x + (3x - 2) = 14
\( 6x + 3x - 2 = 14 \)
\( 9x = 16 \)
\( x = \frac{16}{9} \) - б) 8y - (7y - 142) = 51
\( 8y - 7y + 142 = 51 \)
\( y = 51 - 142 \)
\( y = -91 \) - в) 5 = -1 - (3 - 9x)
\( 5 = -1 - 3 + 9x \)
\( 5 = -4 + 9x \)
\( 9x = 9 \)
\( x = 1 \) - г) 9 - (8x - 11) = 12
\( 9 - 8x + 11 = 12 \)
\( 20 - 8x = 12 \)
\( -8x = 12 - 20 \)
\( -8x = -8 \)
\( x = 1 \) - 4. а) (6x + 1) - (3 - 2x) = 14
\( 6x + 1 - 3 + 2x = 14 \)
\( 8x - 2 = 14 \)
\( 8x = 16 \)
\( x = 2 \) - б) (6 - 2x) + 4 = -5x - 3
\( 6 - 2x + 4 = -5x - 3 \)
\( 10 - 2x = -5x - 3 \)
\( -2x + 5x = -3 - 10 \)
\( 3x = -13 \)
\( x = -\frac{13}{3} \) - в) 12 = (7x - 9) - (11 - x)
\( 12 = 7x - 9 - 11 + x \)
\( 12 = 8x - 20 \)
\( 8x = 32 \)
\( x = 4 \) - г) 11x + 103 = 1 + (12x - 31)
\( 11x + 103 = 1 + 12x - 31 \)
\( 11x + 103 = 12x - 30 \)
\( 103 + 30 = 12x - 11x \)
\( x = 133 \)
Ответ: 1) а) x = -2/3; б) x = 3/5; в) x = -3; г) x = 10; 2) а) x = -5; б) t = -4; в) y = -2; г) p = 11; д) k = 10; е) c = 1.9; 3) а) x = 16/9; б) y = -91; в) x = 1; г) x = 1; 4) а) x = 2; б) x = -13/3; в) x = 4; г) x = 133.