Контрольные задания >
1) a⁻⁸ ⋅ a¹²;
2) a⁷ ⋅ a⁻¹¹;
3) a⁻⁶ ⋅ a¹⁰;
4) a⁻³ : a⁵;
5) a⁻⁴ : a⁻¹²;
6) a¹⁷ ⋅ a⁻²³ : a⁻¹⁵;
1) 7⁵ ⋅ 7⁻⁷;
2) 10⁻¹² ⋅ 10¹⁵;
3) 5⁻¹² : 5⁻¹⁶;
Вопрос:
1) a⁻⁸ ⋅ a¹²;
2) a⁷ ⋅ a⁻¹¹;
3) a⁻⁶ ⋅ a¹⁰;
4) a⁻³ : a⁵;
5) a⁻⁴ : a⁻¹²;
6) a¹⁷ ⋅ a⁻²³ : a⁻¹⁵;
1) 7⁵ ⋅ 7⁻⁷;
2) 10⁻¹² ⋅ 10¹⁵;
3) 5⁻¹² : 5⁻¹⁶;
Смотреть решения всех заданий с листаОтвет:
Решение:
- a⁻⁸ ⋅ a¹² = a-8 + 12 = a4
- a⁷ ⋅ a⁻¹¹ = a7 + (-11) = a-4
- a⁻⁶ ⋅ a¹⁰ = a-6 + 10 = a4
- a⁻³ : a⁵ = a-3 - 5 = a-8
- a⁻⁴ : a⁻¹² = a-4 - (-12) = a-4 + 12 = a8
- a¹⁷ ⋅ a⁻²³ : a⁻¹⁵ = a17 + (-23) : a⁻¹⁵ = a⁻⁶ : a⁻¹⁵ = a-6 - (-15) = a-6 + 15 = a9
- 7⁵ ⋅ 7⁻⁷ = 75 + (-7) = 7⁻²
- 10⁻¹² ⋅ 10¹⁵ = 10-12 + 15 = 10³
- 5⁻¹² : 5⁻¹⁶ = 5-12 - (-16) = 5-12 + 16 = 5⁴
Ответ:
- 1) a⁴
- 2) a⁻⁴
- 3) a⁴
- 4) a⁻⁸
- 5) a⁸
- 6) a⁹
- 1) 7⁻²
- 2) 10³
- 3) 5⁴
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