Ответ:
Преобразуем смешанные числа: \(1\frac{1}{2}=\frac{3}{2}\). Тогда \(\frac{3}{2}-\frac{2}{5}=\frac{15-4}{10}=\frac{11}{10}\).
\(-\frac{2}{3}\cdot\frac{11}{10}=-\frac{11}{15}\).
\(-1\frac{2}{3}=-\frac{5}{3}\), поэтому \(-\frac{5}{3}+\frac{1}{4}=\frac{-20+3}{12}=-\frac{17}{12}\).
\(\frac{5}{6}:\left(-\frac{17}{12}\right)=\frac{5}{6}\cdot\left(-\frac{12}{17}\right)=-\frac{10}{17}\).
\(-5\frac{1}{3}=-\frac{16}{3}\), \(1\frac{1}{3}=\frac{4}{3}\), \(0.5=\frac{1}{2}\).
\(-\frac{16}{3}-\frac{4}{3}\cdot\frac{1}{2}=-\frac{16}{3}-\frac{2}{3}=-6\).
\(-2\frac{3}{4}=-\frac{11}{4}\), \(1\frac{1}{4}=\frac{5}{4}\), \(0.4=\frac{2}{5}\).
\(-\frac{11}{4}+\frac{5}{4}\cdot\frac{2}{5}=-\frac{11}{4}+\frac{1}{2}=-\frac{9}{4}=-2\frac{1}{4}\).
Числитель: \(16-2\frac{1}{3}=16-\frac{7}{3}=\frac{41}{3}\).
\(\frac{\frac{41}{3}}{-4}=\frac{41}{3}\cdot\left(-\frac{1}{4}\right)=-\frac{41}{12}=-3\frac{5}{12}\).
Знаменатель: \(4\frac{1}{7}-15=\frac{29}{7}-\frac{105}{7}=-\frac{76}{7}\).
\(\frac{5}{-\frac{76}{7}}=5\cdot\left(-\frac{7}{76}\right)=-\frac{35}{76}\).
\(-3\frac{1}{6}=-\frac{19}{6}\), \(2\frac{5}{8}=\frac{21}{8}\), \(2\frac{1}{4}=\frac{9}{4}\).
\(\frac{21}{8}:\frac{9}{4}=\frac{21}{8}\cdot\frac{4}{9}=\frac{7}{6}\).
\(-\frac{19}{6}-\frac{7}{6}=-\frac{26}{6}=-\frac{13}{3}=-4\frac{1}{3}\).
\(-2\frac{2}{5}=-\frac{12}{5}\), \(3\frac{1}{15}=\frac{46}{15}\), \(2\frac{1}{11}=\frac{23}{11}\).
\(\frac{46}{15}:\frac{23}{11}=\frac{46}{15}\cdot\frac{11}{23}=\frac{22}{15}\).
\(-\frac{12}{5}+\frac{22}{15}=-\frac{36}{15}+\frac{22}{15}=-\frac{14}{15}\).
Ответ: 1) \(-\frac{11}{15}\); 2) \(-\frac{10}{17}\); 3) \(-6\); 4) \(-2\frac{1}{4}\); 5) \(-3\frac{5}{12}\); 6) \(-\frac{35}{76}\); 7) \(-4\frac{1}{3}\); 8) \(-\frac{14}{15}\).
