Ответ:

1) \(\frac{1}{7}(0.14+2.1-3.5)=\frac{1}{7}(-1.26)=-0.18\).

2) \(\frac{1}{12}(4.8-0.24-1.2)=\frac{1}{12}\cdot3.36=0.28\).

3) Приведём дробные части к знаменателю 28:
\(18\frac{6}{7}+21\frac{3}{4}=18\frac{24}{28}+21\frac{21}{28}=40\frac{17}{28}\).
Тогда \(40\frac{17}{28}:3=\frac{1137}{28}:3=\frac{1137}{84}=\frac{379}{28}=13\frac{15}{28}\).

4) \(15\frac{5}{7}=\frac{110}{7}\), \(20\frac{15}{16}=\frac{335}{16}\).
\(\left(\frac{110}{7}+\frac{335}{16}\right)\cdot\frac{1}{5}=\left(\frac{1760}{112}+\frac{2345}{112}\right)\cdot\frac{1}{5}=\frac{4105}{112}\cdot\frac{1}{5}=\frac{821}{112}=7\frac{37}{112}\).

Ответ: 1) −0,18; 2) 0,28; 3) \(13\frac{15}{28}\); 4) \(7\frac{37}{112}\).