1) $\left(1\frac{2}{13}\cdot 0{,}42+0{,}78\cdot1\frac{2}{13}\right)\cdot1\frac{4}{9}:0{,}6$

Question

Вопрос: $Фото задания: 1) $\left(1\frac{2}{13}\cdot 0{,}42+0{,}78\cdot1\frac{2}{13}\right)\cdot1\frac{4}{9}:0{,}6$$ Фото задания

Accepted Answer

Вынесем общий множитель $1\frac{2}{13}$:

$\left(1\frac{2}{13}\cdot(0{,}42+0{,}78)\right)\cdot1\frac{4}{9}:0{,}6$.

$0{,}42+0{,}78=1{,}2$, а $1\frac{2}{13}=\frac{15}{13}$, $1\frac{4}{9}=\frac{13}{9}$, $0{,}6=\frac{3}{5}$.

$\frac{15}{13}\cdot1{,}2\cdot\frac{13}{9}:\frac{3}{5}=\frac{15}{13}\cdot\frac{6}{5}\cdot\frac{13}{9}\cdot\frac{5}{3}=\frac{10}{3}=3\frac{1}{3}$.

Ответ: $3\frac{1}{3}$.

1) \(\left(1\frac{2}{13}\cdot 0{,}42+0{,}78\cdot1\frac{2}{13}\right)\cdot1\frac{4}{9}:0{,}6\)