Решение:
\[ 3\frac{1}{4} + 0,25 - 1\frac{5}{24} = \frac{13}{4} + \frac{1}{4} - \frac{29}{24} = \frac{14}{4} - \frac{29}{24} = \frac{7}{2} - \frac{29}{24} = \frac{84}{24} - \frac{29}{24} = \frac{55}{24} \]
\[ 2\frac{3}{4} - 4\frac{1}{2} - 0,75 = \frac{11}{4} - \frac{9}{2} - \frac{3}{4} = \frac{11}{4} - \frac{18}{4} - \frac{3}{4} = \frac{11 - 18 - 3}{4} = \frac{-10}{4} = -\frac{5}{2} \]
\[ -4\frac{7}{12} = -\frac{55}{12} \]
\[ \frac{55}{24} : \left(-\frac{5}{2}\right) : \left(-\frac{55}{12}\right) = \frac{55}{24} \times \left(-\frac{2}{5}\right) : \left(-\frac{55}{12}\right) = -\frac{11}{12} : \left(-\frac{55}{12}\right) = -\frac{11}{12} \times \left(-\frac{12}{55}\right) = \frac{11 \times 12}{12 \times 55} = \frac{11}{55} = \frac{1}{5} \]
Ответ: