Ответ:
Решение:
- 1) 6) \( \frac{2}{3} + \frac{1}{6} - \frac{1}{2} = \frac{4}{6} + \frac{1}{6} - \frac{3}{6} = \frac{4+1-3}{6} = \frac{2}{6} = \frac{1}{3} \)
- 2) 6) \( 12 \cdot \left( \frac{2}{3} - \frac{1}{4} \right) = 12 \cdot \left( \frac{8}{12} - \frac{3}{12} \right) = 12 \cdot \frac{5}{12} = 5 \)
- 3) a) \( \left( \frac{1}{9} + \frac{1}{3} \right) : \frac{2}{3} = \left( \frac{1}{9} + \frac{3}{9} \right) : \frac{2}{3} = \frac{4}{9} : \frac{2}{3} = \frac{4}{9} \cdot \frac{3}{2} = \frac{12}{18} = \frac{2}{3} \)
- 3) 6) \( 2 - \frac{2}{3} \cdot \frac{3}{9} = 2 - \frac{6}{27} = 2 - \frac{2}{9} = \frac{18}{9} - \frac{2}{9} = \frac{16}{9} = 1\frac{7}{9} \)
- 3) B) \( \frac{3}{4} : 12 - \frac{1}{32} = \frac{3}{4} \cdot \frac{1}{12} - \frac{1}{32} = \frac{3}{48} - \frac{1}{32} = \frac{1}{16} - \frac{1}{32} = \frac{2}{32} - \frac{1}{32} = \frac{1}{32} \)
- 3) Г) \( 1\frac{1}{5} : \frac{2}{3} + \frac{1}{3} = \frac{6}{5} : \frac{2}{3} + \frac{1}{3} = \frac{6}{5} \cdot \frac{3}{2} + \frac{1}{3} = \frac{18}{10} + \frac{1}{3} = \frac{9}{5} + \frac{1}{3} = \frac{27}{15} + \frac{5}{15} = \frac{32}{15} = 2\frac{2}{15} \)
Ответ: 1) 1/3; 2) 5; 3) a) 2/3; 6) 1 7/9; B) 1/32; Г) 2 2/15.
