1. Найдите значение выражения: 1) 9·(−4/3) − 3 2/3·(−1/4) − 10·4/5·1 7/12; 2) 1 1/2·3 2/3 − 3 2/5·(2 5/6 + 3 5/6·7/25)·3/5; 3) (3 1/4 + 2 1/6) : 2 3/5 − 2 3/5 − 4/9; 4) (6,07·1/20 − 23,4·13/50)·1/4 + 0,074·1/2; 5) (−31,7 : 63,4 − 23,4 : (−11,7))·(−2,4); 6) (−1,2 + 4,32 : (−1,8)) : (−0,001)·(−0,3); 7) (7/16 − (−5/24)) : (−15/16); 8) (10/21 − 25/28) : (−11/14 + 24/35); 9) (−2 2/3 + 2 1/3)·(−1 5/7 : (−4,8)).

1. \(9\cdot(-\frac{4}{3})-3\frac{2}{3}\cdot(-\frac{1}{4})-10\cdot\frac{4}{5}\cdot1\frac{7}{12}=-12+\frac{11}{12}-\frac{125}{3}=-\frac{256}{3}\).
2. \(1\frac{1}{2}\cdot3\frac{2}{3}=\frac{11}{2}\). В скобках: \(2\frac{5}{6}+3\frac{5}{6}\cdot\frac{7}{25}=\frac{17}{6}+\frac{161}{150}=\frac{73}{25}\). Тогда \(\frac{11}{2}-\frac{17}{5}\cdot\frac{73}{25}\cdot\frac{3}{5}=\frac{11}{2}-\frac{3723}{625}=-\frac{1201}{1250}\).
3. \((\frac{13}{4}+\frac{13}{6}):\frac{13}{5}-\frac{13}{5}-\frac49=\frac{65}{12}\cdot\frac5{13}-\frac{13}{5}-\frac49=\frac{25}{12}-\frac{13}{5}-\frac49=-\frac{203}{180}\).
4. \((6,07\cdot\frac1{20}-23,4\cdot\frac{13}{50})\cdot\frac14+0,074\cdot\frac12=(0,3035-6,084)\cdot\frac14+0,037=-1,408625\).
5. \(( -31,7:63,4-23,4:(-11,7))\cdot(-2,4)=(-0,5+2)\cdot(-2,4)=-3,6\).
6. \((-1,2+4,32:(-1,8)):(-0,001)\cdot(-0,3)=(-3,6):(-0,001)\cdot(-0,3)=-1080\).
7. \((\frac7{16}+\frac5{24}):(-\frac{15}{16})=\frac{31}{48}\cdot(-\frac{16}{15})=-\frac{31}{45}\).
8. \((\frac{10}{21}-\frac{25}{28}):( -\frac{11}{14}+\frac{24}{35})=-\frac{55}{84}:\frac{29}{70}=-\frac{275}{174}\).
9. \((-\frac83+\frac73)\cdot((-\frac{12}{7}):(-\frac{24}{5}))=-\frac13\cdot\frac5{14}=-\frac5{42}\).

Ответ: 1) \(-\frac{256}{3}\); 2) \(-\frac{1201}{1250}\); 3) \(-\frac{203}{180}\); 4) \(-1,408625\); 5) \(-3,6\); 6) \(-1080\); 7) \(-\frac{31}{45}\); 8) \(-\frac{275}{174}\); 9) \(-\frac5{42}\).