Решение:
\[ 2\frac{1}{3} = \frac{2 \times 3 + 1}{3} = \frac{7}{3} \]
\[ \frac{9}{16} : \frac{3}{2} = \frac{9}{16} \times \frac{2}{3} = \frac{9 \times 2}{16 \times 3} \]
\[ \frac{9 \times 2}{16 \times 3} = \frac{(3 \times 3) \times 2}{(8 \times 2) \times 3} = \frac{3}{8} \]
\[ \frac{7}{3} - \frac{3}{8} \]
\[ \frac{7 \times 8}{3 \times 8} - \frac{3 \times 3}{8 \times 3} = \frac{56}{24} - \frac{9}{24} = \frac{56 - 9}{24} = \frac{47}{24} \]
\[ \frac{47}{24} = 1 \frac{23}{24} \]
Ответ: $$1\frac{23}{24}$$