Ответ:
а) \(2\frac{3}{4}+4\frac{1}{5}=\frac{11}{4}+\frac{21}{5}=\frac{55+84}{20}=\frac{139}{20}=6\frac{19}{20}\).
б) \(3\frac{1}{6}-1\frac{3}{4}=\frac{19}{6}-\frac{7}{4}=\frac{38-21}{12}=\frac{17}{12}=1\frac{5}{12}\).
в) \(7\frac{8}{15}+1\frac{1}{12}-2\frac{11}{20}=6+\left(\frac{8}{15}+\frac{1}{12}-\frac{11}{20}\right)\).
Приведём дроби к знаменателю 60: \(6+\frac{32+5-33}{60}=6+\frac{4}{60}=6\frac{1}{15}\).
г) \(1\frac{5}{12}+7\frac{5}{6}+0,75=1\frac{5}{12}+7\frac{5}{6}+\frac{3}{4}\).
\(=8+\frac{5}{12}+\frac{10}{12}+\frac{9}{12}=8+\frac{24}{12}=10\).
Ответ: а) \(6\frac{19}{20}\); б) \(1\frac{5}{12}\); в) \(6\frac{1}{15}\); г) \(10\).
