Ответ:

б) \(\frac{2^2}{3-\frac{1}{4} \cdot 3}\) = \(\frac{4}{3 - \frac{3}{4}}\) = \(\frac{4}{\frac{12-3}{4}}\) = \(\frac{4}{\frac{9}{4}}\) = 4 \(\cdot\) \(\frac{4}{9}\) = \(\frac{16}{9}\) = 1\(\frac{7}{9}\)