Правило: чтобы выделить целую часть неправильной дроби, числитель делим на знаменатель. Остаток записываем числителем дробной части.
\(\frac{7}{3}=2\frac{1}{3}\); \(\frac{44}{11}=4\); \(\frac{19}{7}=2\frac{5}{7}\); \(\frac{68}{9}=7\frac{5}{9}\); \(\frac{25}{4}=6\frac{1}{4}\); \(\frac{9}{5}=1\frac{4}{5}\); \(\frac{90}{9}=10\).
\(\frac{12}{5}=2\frac{2}{5}\); \(\frac{35}{6}=5\frac{5}{6}\); \(\frac{8}{3}=2\frac{2}{3}\); \(\frac{51}{5}=10\frac{1}{5}\); \(\frac{26}{13}=2\); \(\frac{15}{3}=5\); \(\frac{17}{5}=3\frac{2}{5}\).
\(\frac{40}{5}=8\); \(\frac{47}{6}=7\frac{5}{6}\); \(\frac{25}{5}=5\); \(\frac{60}{12}=5\); \(\frac{29}{18}=1\frac{11}{18}\); \(\frac{75}{8}=9\frac{3}{8}\); \(\frac{55}{4}=13\frac{3}{4}\).
\(\frac{13}{4}=3\frac{1}{4}\); \(\frac{63}{4}=15\frac{3}{4}\); \(\frac{98}{9}=10\frac{8}{9}\); \(\frac{10}{3}=3\frac{1}{3}\); \(\frac{40}{17}=2\frac{6}{17}\); \(\frac{53}{6}=8\frac{5}{6}\); \(\frac{49}{9}=5\frac{4}{9}\).
Ответ: \(2\frac{1}{3}; 4; 2\frac{5}{7}; 7\frac{5}{9}; 6\frac{1}{4}; 1\frac{4}{5}; 10; 2\frac{2}{5}; 5\frac{5}{6}; 2\frac{2}{3}; 10\frac{1}{5}; 2; 5; 3\frac{2}{5}; 8; 7\frac{5}{6}; 5; 5; 1\frac{11}{18}; 9\frac{3}{8}; 13\frac{3}{4}; 3\frac{1}{4}; 15\frac{3}{4}; 10\frac{8}{9}; 3\frac{1}{3}; 2\frac{6}{17}; 8\frac{5}{6}; 5\frac{4}{9}\).