1. Решите уравнение: 1) a) \(\frac{1-4x}{5} = 1\); 2) a) \(\frac{8x+3}{7} = \frac{10x-1}{7}\)

Решение:

1. 1) a)
1. \(\frac{1-4x}{5} = 1\)
2. \(1 - 4x = 5\)
3. \(-4x = 5 - 1\)
4. \(-4x = 4\)
5. \(x = \frac{4}{-4}\)
6. \(x = -1\)
2. 2) a)
1. \(\frac{8x+3}{7} = \frac{10x-1}{7}\)
2. \(8x + 3 = 10x - 1\)
3. \(3 + 1 = 10x - 8x\)
4. \(4 = 2x\)
5. \(x = \frac{4}{2}\)
6. \(x = 2\)

Ответ: 1) a) \(x = -1\); 2) a) \(x = 2\).