Ответ:

\(3^n=3\cdot3^{n-1}\), сондықтан:

\[\frac{(3^n+3^{n-1})^2}{9^{n-1}}=\frac{(3\cdot3^{n-1}+3^{n-1})^2}{(3^2)^{n-1}}\]

\[=\frac{(4\cdot3^{n-1})^2}{3^{2n-2}}=\frac{16\cdot3^{2n-2}}{3^{2n-2}}=16.\]

Жауабы: \(16\).