1) \(\sqrt{8}+3\sqrt{2}+\sqrt{32}\)

Упростим корни:

\(\sqrt{8}=\sqrt{4\cdot2}=2\sqrt{2}\), \(\sqrt{32}=\sqrt{16\cdot2}=4\sqrt{2}\).

Тогда:

\(\sqrt{8}+3\sqrt{2}+\sqrt{32}=2\sqrt{2}+3\sqrt{2}+4\sqrt{2}=9\sqrt{2}\).

Ответ: \(9\sqrt{2}\).