1 вариант. 1) Вычислить: 1) 0,1√2500; 2) (1/14)√196 − 10√0,01; 3) (6/7)·√(1 13/36); 4) 10√3,24 − √256; 5) (1/2)·√196 + 15·√0,36; 6) 5 − (1/7)·√(1 27/169).

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Accepted Answer

\(0{,}1\sqrt{2500}=0{,}1\cdot50=5\).
\(\frac{1}{14}\sqrt{196}-10\sqrt{0{,}01}=\frac{14}{14}-10\cdot0{,}1=1-1=0\).
\(\frac{6}{7}\sqrt{1\frac{13}{36}}=\frac{6}{7}\sqrt{\frac{49}{36}}=\frac{6}{7}\cdot\frac{7}{6}=1\).
\(10\sqrt{3{,}24}-\sqrt{256}=10\cdot1{,}8-16=2\).
\(\frac{1}{2}\sqrt{196}+15\sqrt{0{,}36}=7+15\cdot0{,}6=16\).
\(5-\frac{1}{7}\sqrt{1\frac{27}{169}}=5-\frac{1}{7}\sqrt{\frac{196}{169}}=5-\frac{2}{13}=\frac{63}{13}\).

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