1) Вычислить: 1) 0,2√3600; 2) (1/22)√121 − 5√0,49; 3) (5/7)·√(1 24/25); 4) 10√2,89 − √676; 5) 0,5·√0,04 + (1/6)·√144; 6) 2·√(1 9/16) − 1.

1. \(0.2\sqrt{3600}=0.2\cdot60=12\).
2. \(\frac{1}{22}\sqrt{121}-5\sqrt{0.49}=\frac{11}{22}-5\cdot0.7=0.5-3.5=-3\).
3. \(\frac{5}{7}\sqrt{1\frac{24}{25}}=\frac{5}{7}\sqrt{\frac{49}{25}}=\frac{5}{7}\cdot\frac{7}{5}=1\).
4. \(10\sqrt{2.89}-\sqrt{676}=10\cdot1.7-26=17-26=-9\).
5. \(0.5\sqrt{0.04}+\frac{1}{6}\sqrt{144}=0.5\cdot0.2+\frac{12}{6}=0.1+2=2.1\).
6. \(2\sqrt{1\frac{9}{16}}-1=2\sqrt{\frac{25}{16}}-1=2\cdot\frac{5}{4}-1=1.5\).

Ответ: 1) 12; 2) −3; 3) 1; 4) −9; 5) 2,1; 6) 1,5.