\( 2\frac{1}{3} = \frac{2\cdot3+1}{3} = \frac{7}{3} \)
\( 1\frac{3}{7} = \frac{1\cdot7+3}{7} = \frac{10}{7} \)
\( \frac{5}{8} - \frac{8}{3} = \frac{5\cdot3}{8\cdot3} - \frac{8\cdot8}{3\cdot8} = \frac{15}{24} - \frac{64}{24} = \frac{15-64}{24} = -\frac{49}{24} \)
\( \frac{7}{3} : \left(-\frac{49}{24}\right) = \frac{7}{3} \cdot \left(-\frac{24}{49}\right) = -\frac{7\cdot24}{3\cdot49} = -\frac{7\cdot3\cdot8}{3\cdot7\cdot7} = -\frac{8}{7} \)
\( 2 \cdot \frac{10}{7} = \frac{20}{7} \)
\( -\frac{8}{7} + \frac{20}{7} = \frac{20-8}{7} = \frac{12}{7} \)
\( \frac{12}{7} = 1\frac{5}{7} \)
Ответ: 1\(\frac{5}{7}\).