1. Вычислите: 5\(\frac{1}{2}\) + 1\(\frac{1}{6}\); 6\(\frac{2}{5}\) - 1\(\frac{1}{10}\); б) 2\(\frac{4}{9}\) + 3\(\frac{1}{2}\); д) 4\(\frac{5}{7}\) - 1\(\frac{2}{3}\); в) 5\(\frac{7}{12}\) + 1\(\frac{7}{8}\); е) 3\(\frac{1}{2}\) - 1\(\frac{2}{3}\).

1. Вычисления:

1. \( 5\frac{1}{2} + 1\frac{1}{6} = \frac{11}{2} + \frac{7}{6} = \frac{33}{6} + \frac{7}{6} = \frac{40}{6} = 6\frac{4}{6} = 6\frac{2}{3} \)
2. \( 6\frac{2}{5} - 1\frac{1}{10} = \frac{32}{5} - \frac{11}{10} = \frac{64}{10} - \frac{11}{10} = \frac{53}{10} = 5\frac{3}{10} \)
3. \( 2\frac{4}{9} + 3\frac{1}{2} = \frac{22}{9} + \frac{7}{2} = \frac{44}{18} + \frac{63}{18} = \frac{107}{18} = 5\frac{17}{18} \)
4. \( 4\frac{5}{7} - 1\frac{2}{3} = \frac{33}{7} - \frac{5}{3} = \frac{99}{21} - \frac{35}{21} = \frac{64}{21} = 3\frac{1}{21} \)
5. \( 5\frac{7}{12} + 1\frac{7}{8} = \frac{67}{12} + \frac{15}{8} = \frac{134}{24} + \frac{45}{24} = \frac{179}{24} = 7\frac{11}{24} \)
6. \( 3\frac{1}{2} - 1\frac{2}{3} = \frac{7}{2} - \frac{5}{3} = \frac{21}{6} - \frac{10}{6} = \frac{11}{6} = 1\frac{5}{6} \)

Ответ: 1. \(6\frac{2}{3}\); 2. \(5\frac{3}{10}\); б) \(5\frac{17}{18}\); д) \(3\frac{1}{21}\); в) \(7\frac{11}{24}\); е) \(1\frac{5}{6}\).